javascript - 获取重复事件和非重复事件的单个统一实例

Question

我正在尝试获取重复事件的一个统一实例，以及我在该实例中所做的更改以反射(reflect)在该重复事件的所有实例中。

calendar.getEvents 返回重复系列中每个事件的单个实例。即，如果我对该实例进行任何更改(例如删除它)，则只有该特定实例会被删除。我尝试使用 getEventSeries() 和 deleteEventSeries() 但这些不会反射(reflect)在数组中，所以我每次删除时都会调用 getEvents 。这是最好的方法吗？或者有替代方案吗？

//The object of the following code is to delete all events in a calendar
function delete_events(calendar) {
  var fromDate = new Date("January 1, 1900 00:00:00");
  var toDate = new Date("January 1, 2100 00:00:00");
  var events = calendar.getEvents(fromDate, toDate);

  while (events.length > 0) {
    var ev = events[0];
    var es = ev.getEventSeries();
    es.deleteEventSeries();
    Logger.log('Deleted: ' + es.getTitle());

    events = calendar.getEvents(fromDate, toDate);
  }
}

Answer 1

由于 eventsSeries 具有相同的 ID，您只需记住这些 ID 即可简化流程，并在后续迭代中跳过这些事件。

这是一个简单的测试代码:

function test(){
  var cal = CalendarApp.getCalendarsByName('some calendar name you own')[0];
  delete_events(cal);
}

function delete_events(cal) {
  var fromDate = new Date("January 1, 2014 00:00:00");
  var toDate = new Date("January 1, 2100 00:00:00");
  var events = cal.getEvents(fromDate, toDate);
  var IDs = [];
  for(var n in events){
    Logger.log(events[n].getTitle());
    var id = events[n].getId();
    if(IDs.indexOf(id)>-1){continue};
    try{
      cal.getEventSeriesById(id).deleteEventSeries();
      IDs.push(id);
      Logger.log(events[n].getTitle()+' was deleted,  ID = '+events[n].getId());
    }catch(err){Logger.log(events[n].getTitle()+' on '+Utilities.formatDate(events[n].getStartTime(),cal.getTimeZone(),'yyyy/MMM/dd')+" was not deleted,you don't have the right to modify it");}
  }
}