rust - 结果失败返回 `map_err`

Question

我正在弄清楚为什么在返回 map_err 时以下失败:

Compiling playground v0.0.1 (/playground)
error[E0308]: mismatched types
  --> src/main.rs:37:5
   |
36 | fn R() -> Result<i32, MyError> {
   |           -------------------- expected `std::result::Result<i32, MyError>` because of return type
37 |     decode().map_err(|e| Err(MyError {v: "changed".to_string() }))
   |     ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ expected struct `MyError`, found enum `std::result::Result`
   |
   = note: expected enum `std::result::Result<_, MyError>`
              found enum `std::result::Result<_, std::result::Result<_, MyError>>`

error: aborting due to previous error

For more information about this error, try `rustc --explain E0308`.
error: could not compile `playground`.

如果我使用 match 并手动映射它，它就可以工作。

代码:

use std::error::Error;
use std::fmt;
use std::fmt::Display;

#[derive(Debug)]
struct MyError {
    v: String,
}

impl MyError {
    fn new() -> MyError {
        MyError {
            v: "oh no!".to_string()
        }
    }

    fn change_message(&mut self, new_message: &str) {
        self.v = new_message.to_string();
    }
}

impl Error for MyError {}

impl Display for MyError {
    fn fmt(&self, f: &mut fmt::Formatter<'_>) -> fmt::Result {
        write!(f, "MyError: {}", &self.v)
    }
}

fn decode() -> Result<i32, MyError> {
    Err(
        MyError::new()
    )
}

fn R() -> Result<i32, MyError> {
    decode().map_err(|e| Err(MyError {v: "changed".to_string() }))
}

fn main() {
    let d = R();
    match d {
        Ok(t) => println!("t {}", t),
        Err(e) => println!("e {}", e)
    }
}

Answer 1

如果您查看 signature for map_err您会看到它需要一个接受错误类型并返回错误类型而不是Result的闭包。

decode().map_err(|e| MyError {v: "changed".to_string() })