loops - 如何在一个从索引i和i + 1取值的数组上创建迭代器？

Question

我创建了一个在Rust游乐场中运行的小示例:

#[derive(Clone)]
pub struct Person {
    pub firstname: Vec<u8>,
    pub surname: Vec<u8>,
}

fn main() {
    let p0 = Person {
        firstname: vec![0u8; 5],
        surname: vec![1u8; 5],
    };
    let p1 = Person {
        firstname: vec![2u8; 7],
        surname: vec![3u8; 2],
    };
    let p2 = Person {
        firstname: vec![4u8; 8],
        surname: vec![5u8; 8],
    };
    let p3 = Person {
        firstname: vec![6u8; 3],
        surname: vec![7u8; 1],
    };

    let people = [p0, p1, p2, p3];

    for i in 0..people.len() {
        if i + 1 < people.len() {
            println!(
                "{:?}",
                (people[i].firstname.clone(), people[i + 1].surname.clone())
            )
        }
    }
}

给定数组 people，我想对其元素进行迭代，并在索引 person处收集 i的名字和在索引 i+1处的人的姓氏的元组。这个简单的for循环可以完成这项工作，但让我们假设，我想将此类元组传递给某些函数 println，而不是 f。我可以在 for循环中轻松地做到这一点，但是我想了解是否可以使用迭代器 iter()(然后再根据需要应用 collect()或 fold函数)而不是 for循环来实现该功能？

Answer 1

我会使用 slice::windows :

for window in people.windows(2) {
    println!("{:?}", (&window[0].firstname, &window[1].surname))
}

也可以看看:

Creating a sliding window iterator of slices of chars from a String

Are there equivalents to slice::chunks/windows for iterators to loop over pairs, triplets etc?

Pattern matching on slices

How to convert a slice into an array reference?