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websocket - 在BusReader和Warp WebSocket接收器之间转发消息会留下未占用的缓冲区?

转载 作者:行者123 更新时间:2023-12-03 11:31:14 24 4
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我正在尝试创建一个websocket服务器(以及HTTP,因此使用warp),该服务器通过websocket将消息从一个源(MQTT订阅)转发到许多客户端。除了客户端在广播第二条消息之前没有收到第一条Websocket消息之外,这似乎基本上可以正常工作。然后总是留下一条消息,直到最后再也没有收到最后一条消息。对我来说,问题似乎是在ws_connected函数中从未完全刷新过的发送缓冲区。
我使用futures::stream::iterBusReader转换为流,然后将消息映射到WebSocket Sink所需的所需Ok(Message)类型。官方的warp websocket聊天示例使用类似的构造在流之间转发:https://github.com/seanmonstar/warp/blob/42fd14fdab8145d27ae770fe4b5c843a99bc2a44/examples/websockets_chat.rs#L62
在这个简化的示例中,服务器通过总线广播值0-9。一个websocat客户端(和Firefox中的JS websocket客户端)接收到0-8消息-尽管总是在广播和服务器标准输出之后出现-但9个消息永远不会到达。 async_bus_print函数会按时接收所有值,这证明消息至少可以毫无问题地通过总线。
这是服务器进程的输出:

async bus_print started
0
async bus: "0"
1
async bus: "1"
2
async bus: "2"
3
async bus: "3"
4
async bus: "4"
5
async bus: "5"
6
async bus: "6"
7
async bus: "7"
8
async bus: "8"
9
async bus: "9"
有问题的代码:
use std::{sync::{Arc, RwLock}, thread};

use bus::{Bus, BusReader};
use futures::StreamExt;
use warp::ws::{Message, WebSocket};
use warp::Filter;

async fn ws_connected(ws: WebSocket, rx: BusReader<String>) {
let (ws_tx, _ws_rx) = ws.split();

thread::spawn(|| {
futures::executor::block_on(async move {
if let Err(e) = futures::stream::iter(rx.into_iter())
.map(|ws_msg| Ok(Message::text(ws_msg)))
.forward(ws_tx)
.await
{
eprintln!("Goodbye, websocket user: {}", e);
}
});
});
}

async fn async_bus_print(mut rx: BusReader<String>) {
println!("async bus_print started");
thread::spawn(||
futures::executor::block_on(async move {
while let Some(msg) = futures::stream::iter(rx.iter()).next().await {
println!("async bus: {:#?}", msg);
}
})
);
}

async fn bus_tx(tx: Arc<RwLock<Bus<String>>>) {
for i in 0..10u8 {
tx.write().unwrap().broadcast(format!("{}", i));
println!("{}", i);
tokio::time::delay_for(std::time::Duration::from_secs(1)).await;
}
}

#[tokio::main]
async fn main() {
let bus = Arc::new(RwLock::new(Bus::new(20)));
let bus2 = Arc::clone(&bus);
let rx = warp::any().map(move || bus2.write().unwrap().add_rx());
let rx2 = bus.write().unwrap().add_rx();

let ws = warp::path("ws")
.and(warp::ws())
.and(rx)
.map(|ws: warp::ws::Ws, rx| ws.on_upgrade(move |socket| ws_connected(socket, rx)));

futures::join!(
async_bus_print(rx2),
bus_tx(bus),
warp::serve(ws).run(([127, 0, 0, 1], 3030)),
);
}
如何跟踪并消除此“缓冲”问题?
希望我已经解释得足够好了。请让我知道是否可以提供更多信息。谢谢你的帮助。

最佳答案

尽管我仍然无法弄清数据未刷新的根本原因,但由于有一些乐于助人的人在Reddit上工作,我有一些更好的替代解决方案。
如果您不首先拆分WebSocket,它似乎可以正常工作:

async fn ws_connected(ws: WebSocket, rx: BusReader<String>) {
thread::spawn(|| {
futures::executor::block_on(async move {
if let Err(e) = futures::stream::iter(rx.into_iter())
.map(|ws_msg| Ok(Message::text(ws_msg)))
.forward(ws)
.await
{
eprintln!("Goodbye, websocket user: {}", e);
}
});
});
}
如果您在代码中包含 send,则仍可以拆分流并将数据 forward(而不是 futures::SinkExt)分离到WebSocket的tx端:
async fn ws_connected(ws: WebSocket, mut rx: BusReader<String>) {
use futures::SinkExt;

let (mut ws_tx, ws_rx) = ws.split();

while let Ok(msg) = rx.recv() {
ws_tx.send(Message::text(msg)).await.unwrap();
// `send` automatically flushes the sink
}
}
最终,我认为tokio的 broadcast channel 比 bus更适合我的异步多生产者,多消费者 channel 通信需求:
use futures::StreamExt;
use tokio::sync::broadcast;
use warp::ws::{Message, WebSocket};
use warp::Filter;

async fn ws_connected(ws: WebSocket, recv: broadcast::Receiver<String>) {
let (ws_tx, _ws_rx) = ws.split();

recv.map(|s| Ok(Message::text(s.unwrap())))
.forward(ws_tx)
.await
.unwrap();
}

async fn async_bus_print(mut recv: broadcast::Receiver<String>) {
println!("async bus_print started");
while let Some(msg) = recv.next().await {
println!("async bus: {:#?}", msg.unwrap());
}
}

async fn bus_tx(tx: broadcast::Sender<String>) {
for i in 0..10u8 {
tx.send(format!("{}", i)).unwrap();
println!("{}", i);
tokio::time::delay_for(std::time::Duration::from_secs(1)).await;
}
}

#[tokio::main]
async fn main() {
let (send, recv) = broadcast::channel::<String>(32);
let send2 = send.clone();
let rx = warp::any().map(move || send2.subscribe());

let ws = warp::path("ws")
.and(warp::ws())
.and(rx)
.map(|ws: warp::ws::Ws, recv| ws.on_upgrade(move |socket| ws_connected(socket, recv)));

let (abp, tx, warp) = futures::join!(
tokio::spawn(async_bus_print(recv)),
tokio::spawn(bus_tx(send)),
tokio::spawn(warp::serve(ws).run(([127, 0, 0, 1], 3030))),
);

abp.unwrap();
tx.unwrap();
warp.unwrap();
}

关于websocket - 在BusReader和Warp WebSocket接收器之间转发消息会留下未占用的缓冲区?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/65571775/

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