javascript - Ajax返回成功但不更新数据库

Question

这是我的 javascript 和 ajax 代码，它返回成功，但数据库没有更新，有什么想法吗？谢谢。已解决

        function send_data()
        {
        var name = $('#name').val();
        var keywords = $('#keywords').val();
        var description = $('#description').val();
        var cat1 = $('#cat1').val();
        var cat2 = $('#cat2').val();
        var cat3 = $('#cat3').val();
        var id = $('#id').val();
        $.ajax({
        url: "updateproductsgo.php?name=" + name + "&keywords=" + keywords + "&description=" + description + "&cat1=" + cat1 + "&cat2=" + cat2 + "&cat3" + cat3 + "&id=" + id,
        type: 'GET',
        success: function(result) {
        alert('success');
        // use the result as you wish in your html here
        jQuery("#results").html(result);
        }});

        }

这是我在 updateproductsgo.php 上的代码

$con=mysql_connect("localhost","root","");
$db=mysql_select_db("xxx",$con);
$id=$_GET['id'];
$name=$_GET['name'];
$keywords=$_GET['keywords']; 
$description=$_GET['description']; 
$cat1=$_GET['cat1'];
$cat2=$_GET['cat2'];
$cat3=$_GET['cat3'];

$query = "UPDATE xxx SET name = '$name', keywords = '$keywords', description = '$description', cat1 = '$cat1', cat2 = '$cat2', cat3 = '$cat3' WHERE id = '$id'";
echo $query;
mysql_query($query) or die(mysql_error());

更新了 $query，但没有什么区别。

解决了!网址中缺少 =。基本的东西!!

Answer 1

您的更新查询缺少逗号

$query = "UPDATE products SET name = '$name', keywords = '$keywords', description = '$description', cat1 = '$cat1', cat2 = '$cat2', cat3 = '$cat3' WHERE id = $id";