msbuild - 使用MSBuild生成多个配置

Question

我正在尝试编辑我的项目文件，以使我拥有一个可以一次构建多个构建配置的项目。我使用批处理方法和MSBuild任务(参见下文)完成了此操作。

如果运行脚本，则会收到以下错误消息:

Error 103 The OutputPath property is not set for project "ThisMSBuildProjectFile.csproj". Please check to make sure that you have specified a valid combination of Configuration and Platform for this project. Configuration='Debug' Platform='AnyCPU'.

如果我从MSBuild任务添加或省略OutputPath，则会得到此信息。如果使用VS2010调试器来逐步执行脚本并调用MSBuild任务-调试器将再次进入文件，然后进入OutputPath，那么afaik，它应该获取该值，不是吗？

任何帮助都将不胜感激-这让我发疯。谢谢，保罗。

ThisMSBuildProjectFile.csproj(多余的东西取出来):

<?xml version="1.0" encoding="utf-8"?>
<Project ToolsVersion="4.0" xmlns="http://schemas.microsoft.com/developer/msbuild/2003" DefaultTargets="Build">

  <!-- Only Import normal targets if not building multiple projects -->
  <Import Project="$(MSBuildToolsPath)\Microsoft.CSharp.targets" Condition="'$(Configuration)|$(Platform)' != 'AllBuild|AnyCPU' "/>

  <PropertyGroup Condition=" '$(Configuration)|$(Platform)' == '' ">
    <DebugType>pdbonly</DebugType>
    <Optimize>true</Optimize>
    <OutputPath>C:\Folder\Etc\Output\$(Configuration)\</OutputPath>
    <OutDir>C:\Folder\Etc\Output\$(Configuration)\</OutDir>
    <BaseOutputPath>C:\Folder\Etc\Output\$(Configuration)\</BaseOutputPath>
    <DefineConstants>TRACE</DefineConstants>
    <ErrorReport>prompt</ErrorReport>
    <WarningLevel>4</WarningLevel>
  </PropertyGroup>

  <!-- Common -->
  <PropertyGroup Condition=" '$(Configuration)|$(Platform)' == 'Debug|AnyCPU' ">
    <Platform>AnyCPU</Platform>
    <!-- Repeated properties from above here (including, of course, OutputPath) -->  
   </PropertyGroup>
  <PropertyGroup Condition=" '$(Configuration)|$(Platform)' == 'Release|AnyCPU' ">
    <!-- Repeated properties from above here (including, of course, OutputPath) --> 
  </PropertyGroup>

  <ItemGroup>
    <Projects Include="C:\Folder\Etc\ThisMSBuildProjectFile.csproj" />
  </ItemGroup>

   <!-- Call this project file again, but with a different configuration - if this was working, this would call multiple  build configs -->
  <Target Name="Build" Condition="'$(Configuration)|$(Platform)' == 'AllBuild|AnyCPU' ">
    <Message Text="hm!"/>
    <!-- Tried thiswith and without the OutputPath property - makes no difference. -->
   <MSBuild  Projects="@(Projects)" Properties="Configuration=Debug;OutputPath=C:\Folder\Etc\Output\" ToolsVersion="4.0" Condition="'$(Configuration)|$(Platform)' == 'AllBuild|AnyCPU' "/>
 </Target>

   <PropertyGroup Condition=" '$(Configuration)|$(Platform)' == 'AllBuild|AnyCPU' ">
    <!-- Repeated properties from above here (including, of course, OutputPath) --> 
  </PropertyGroup>

  <!-- Project files -->
  <ItemGroup>
    <Reference Include="System" />
    <Reference Include="System.Core" />
  </ItemGroup>
  <ItemGroup>
    <Compile Include="Properties\AssemblyInfo.cs" />
    <Compile Include="Blah\Blah.cs" />
  </ItemGroup>

Answer 1

重要的是要意识到，当您使用“MSBuild”任务时，将启动一个新的子MSBuild进程。这意味着您在父MSBuild进程中定义的所有项和属性都将而不是自动传递给子MSBuild进程 /从其可见。 。

为了回答您的问题，我编写了以下独立的示例，该示例针对所有指定的配置运行子MSBuild项目:

首先，为您的MSBuild实验创建一个目录(例如，我使用Properties)

在此目录中，创建第一个文件MSBuild:

<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003" DefaultTargets="Build" ToolsVersion="4.0">
    <ItemGroup>
        <ConfigList Condition=" '@(ConfigList)' == '' and $(Config) != '' " Include="$(Config.Split('+'))" /><!-- parse all requested configurations into a list -->
        <ConfigList Condition=" '@(ConfigList)' == '' " Include="Debug" /><!-- if no configurations were specified, default to Debug -->
    </ItemGroup>
    <!--

    Build the child project for each requested configuration. -->
    <Target Name="Build">
        <MSBuild Projects="$(MSBuildProjectDirectory)\child.proj" Properties="Configuration=%(ConfigList.Identity);OutputPath=$(MSBuildProjectDirectory)\bin\%(ConfigList.Identity)" Targets="Build" />
    </Target>
</Project>

在同一目录中，创建第二个文件<MSbuild Properties="..." />(在您的情况下，这将是您要构建的实际C#项目，但是由于我试图说明我的观点，因此我使用了一个简单的子项目，而不是运行C#编译器只是打印属性值:-))

<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003" DefaultTargets="Build" ToolsVersion="4.0">
    <Target Name="Build">
        <Message Text="Building configuration $(Configuration) with output path $(OutputPath)" Importance="High" />
    </Target>
</Project>

现在您可以运行该示例。首先是默认值，如果您未明确指定要配置的配置:

C:\WINDOWS\Microsoft.NET\Framework\v4.0.30319\msbuild main.proj
> (cut the noise)
> Build:
>   Building configuration Debug with output path C:\temp_c\d\bin\Debug

然后显式指定多个配置:

C:\WINDOWS\Microsoft.NET\Framework\v4.0.30319\msbuild main.proj /property:Config=Debug+Release+Staging+Production
> (cut the noise)
> Build:
>   Building configuration Debug with output path C:\temp_c\d\bin\Debug
> Build:
>   Building configuration Release with output path C:\temp_c\d\bin\Release
> Build:
>   Building configuration Staging with output path C:\temp_c\d\bin\Staging
> Build:
>   Building configuration Production with output path C:\temp_c\d\bin\Production

您应该能够使这种技术适应您的情况。