用于 logrotate 日志的 Powershell 脚本

Question

好的。所以我想编写一个 PowerShell 脚本来模拟(某种)在 Linux 中找到的 LogRotate 选项。对于单个文件:没问题。但我希望它适用于文件夹内的所有文件。但是......它不起作用......完全没有。我尝试用 foreach-object 来做，但它仍然不起作用。我是 PowerShell 编程的新手，所以如果我的脚本看起来不那么好，请原谅我干净的。
这里是:

function RotateLog {
    $log = "C:\Users\nvali\Desktop\scripts"
    Push-Location $log
    $target = Get-ChildItem $log -Filter "*.txt"
    $threshold = 300
    $datetime = Get-Date -uformat "%Y-%m-%d-%H%M"
    #$target_path =Get-ChildItem $log
    $filesize = $target.length/1MB
    $target | ForEach-Object {
        if ($filesize -ge $threshold) { 
            $filename = $_.name -replace $_.extension,"" 
            $newname = "${filename}_${datetime}.log_old"
            Rename-Item $_.fullname $newname
            $rotationmessage = ""
            Write-Host "Done" 
        }
        echo "$rotationmessage"
    }
}

Answer 1

您需要检查 foreach 中每个文件的文件大小为 LotPings提到，并作为 BenH评论说，在 foreach 中你需要使用 $_访问正在访问的当前对象。

这个脚本对我有用，没有任何错误。

function RotateLog {
$log = "C:\logDir"
$target = Get-ChildItem $log -Filter "*.txt"
$threshold = 30
$datetime = Get-Date -uformat "%Y-%m-%d-%H%M"
$target | ForEach-Object {
    if ($_.Length -ge $threshold) { 
        Write-Host "file named $($_.name) is bigger than $threshold KB"
        $newname = "$($_.BaseName)_${datetime}.log_old"
        Rename-Item $_.fullname $newname
        Write-Host "Done rotating file" 
    }
    else{
         Write-Host "file named $($_.name) is not bigger than $threshold KB"
    }
    Write-Host " "
}