javascript - 根据条件从嵌套的对象数组中删除项目

Question

在我的应用程序中，我有从服务器返回的数据，如下所示。它有很深的嵌套:

var data = [{
    name: "root",
    children: [{
            name: "Parent1",
            children: [{
                    name: "Parent1-child1",
                    children: [{
                            name: "Parent1-child1-grandchild1",
                            children: [{
                                name: "Parent1-child1-grandchild1-last",
                                children:[]
                            }]
                        },
                        {
                            name: "Parent1-child1-grandchild2",
                            children: []
                        },
                        {
                            name: "Parent1-child1-grandchild3",
                            children: []
                        }
                    ]
                },
                {
                    name: "Paren1-child2",
                    children: [{
                            name: "Parent1-chil2-grandchild1",
                            children: []
                        },
                        {
                            name: "Parent1-child2-grandchild2",
                            children: [{
                                name: "Parent1-child2-grandchild2-last",
                                children: []
                            }]
                        },
                        {
                            name: "Parent1-child2-grandchild3",
                            children: []
                        }
                    ]
                },
                {
                    name: "Parent1-child3",
                    children: []
                }
            ]
        },
        {
            name: "Parent2",
            children: [{
                    name: "Parent2-child1",
                    children: []
                },
                {
                    name: "Parent2-child2",
                    children: [{
                            name: "Parent2-child2-grandchild1",
                            children: []
                        },
                        {
                            name: "Parent2-child2-grandchild2",
                            children: [{
                                name: "Parent2-child2-grandchild2-last",
                                children: []
                            }]
                        }
                    ]
                }
            ]
        },
        {
            name: "Parent3",
            children: []
        }
    ]
}];

要求是遍历所有对象(也包括深层嵌套)，如果 children 属性的值为空数组，则删除该对象。所以 输出应如下

var data = [{
    name: "root",
    children: [{
            name: "Parent1",
            children: [{
                    name: "Parent1-child1",
                    children: [{
                            name: "Parent1-child1-grandchild1",
                            children: []
                        },
                    ]
                },
                {
                    name: "Paren1-child2",
                    children: [
                        {
                            name: "Parent1-child2-grandchild2",
                            children: []
                        },
                    ]
                },
            ]
        },
        {
            name: "Parent2",
            children: [
                {
                    name: "Parent2-child2",
                    children: [
                        {
                            name: "Parent2-child2-grandchild2",
                            children: []
                        }
                    ]
                }
            ]
        }
    ]
}];

我已经尝试了以下代码，但它没有按预期工作。请让我知道如何达到预期的结果。

function checkChildrens(arr) {
    arr.forEach((ele,i) => {
    if(ele.hasOwnProperty('children')) {
        checkChildrens(ele['children']) 
    } else {
        arr.splice(i,1)
    }
    })
}
checkChildrens(data);

在这种情况下，我也尝试过使用过滤器方法。它无法正常工作。

arr.filter((ele,i)=>{
   if(ele.hasOwnProperty('children') && ele.children.length !== 0 ){
      removeEmpty(ele.children)
   }else{
        return false;
    }
    return true;
})

Answer 1

您可以通过检查子数组长度来重建新对象。

function filter(array) {
    return array.reduce((r, o) => {
        if (o.children && o.children.length) {
            r.push(Object.assign({}, o, { children: filter(o.children) }));
        }
        return r;
    }, []);
}

var data = [{ name: "root", children: [{ name: "Parent1", children: [{ name: "Parent1-child1", children: [{ name: "Parent1-child1-grandchild1", children: [{ name: "Parent1-child1-grandchild1-last", children: [] }] }, { name: "Parent1-child1-grandchild2", children: [] }, { name: "Parent1-child1-grandchild3", children: [] }] }, { name: "Paren1-child2", children: [{ name: "Parent1-chil2-grandchild1", children: [] }, { name: "Parent1-child2-grandchild2", children: [{ name: "Parent1-child2-grandchild2-last", children: [] }] }, { name: "Parent1-child2-grandchild3", children: [] }] }, { name: "Parent1-child3", children: [] }] }, { name: "Parent2", children: [{ name: "Parent2-child1", children: [] }, { name: "Parent2-child2", children: [{ name: "Parent2-child2-grandchild1", children: [] }, { name: "Parent2-child2-grandchild2", children: [{ name: "Parent2-child2-grandchild2-last", children: [] }] }] }] }, { name: "Parent3", children: [] }] }],
    result = filter(data);

console.log(result);

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删除所有嵌套的空子项的方法(最后一个除外。它有一个空对象，但没有 children 属性)。

function filter(array) {
    return array.reduce((r, o) => {
        if (o.children) {
            var children = filter(o.children);
            if (children.length) r.push(Object.assign({}, o, { children }));
        } else {
            r.push(o);
        }
        return r;
    }, []);
}

var data = [{ name: "root", children: [{ name: "Parent1", children: [{ name: "Parent1-child1", children: [{ name: "Parent1-child1-grandchild1", children: [{ name: "Parent1-child1-grandchild1-last", children: [] }] }, { name: "Parent1-child1-grandchild2", children: [] }, { name: "Parent1-child1-grandchild3", children: [] }] }, { name: "Paren1-child2", children: [{ name: "Parent1-chil2-grandchild1", children: [] }, { name: "Parent1-child2-grandchild2", children: [{ name: "Parent1-child2-grandchild2-last", children: [] }] }, { name: "Parent1-child2-grandchild3", children: [] }] }, { name: "Parent1-child3", children: [] }] }, { name: "Parent2", children: [{ name: "Parent2-child1", children: [] }, { name: "Parent2-child2", children: [{ name: "Parent2-child2-grandchild1", children: [] }, { name: "Parent2-child2-grandchild2", children: [{ name: "Parent2-child2-grandchild2-last", children: [] }] }] }] }, { name: "Parent3", children: [{}] }] }],
    result = filter(data);

console.log(result);

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