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windows - C++将32位bmp图像转换为24位bmp和16位bmp

转载 作者:行者123 更新时间:2023-12-03 11:10:43 27 4
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尝试将32位图像B8R8G8A8转换为24位图像R8G8B8和16位R5G5B5。
但是结果很奇怪,也许我不明白如何正确转换图像。如何正确执行并修复颜色?

输入图像:

enter image description here

Convert32to16()之后:

enter image description here

Convert32to24()之后:

enter image description here

stdafx.h

// stdafx.h : include file for standard system include files,
// or project specific include files that are used frequently, but
// are changed infrequently
//

#pragma once

#include "targetver.h"

#include <stdio.h>
#include <tchar.h>
#include <iostream>
#include <fstream>
#include <windows.h>


// TODO: reference additional headers your program requires here

ImageConverter.cpp
#include "stdafx.h"


using std::cout;
using std::endl;
using std::ofstream;
using std::ifstream;

void Convert32to24(void* B8G8R8A8, BYTE* R8G8B8, int width, int height)
{
long B8G8R8A8Size = (width * height * 4);
long j = 0;
for (long i = 0; i < (B8G8R8A8Size - 3); i = i + 4)
{
BYTE Red = ((PBYTE)B8G8R8A8)[i + 2];
BYTE Green = ((PBYTE)B8G8R8A8)[i + 1];
BYTE Blue = ((PBYTE)B8G8R8A8)[i];
BYTE Alpha = ((PBYTE)B8G8R8A8)[i + 3];

R8G8B8[j] = Red;
R8G8B8[j + 1] = Green;
R8G8B8[j + 2] = Blue;
j = j + 3;
}
}

void Convert32to16(void* B8G8R8A8, BYTE* R5G5B5, int width, int height)
{
long B8G8R8A8Size = (width * height * 4);

long j = 0;
for (long i = 0; i < (B8G8R8A8Size - 3); i = i + 4)
{
BYTE Red = ((PBYTE)B8G8R8A8)[i + 2] >> 3;
BYTE Green = ((PBYTE)B8G8R8A8)[i + 1] >> 3;
BYTE Blue = ((PBYTE)B8G8R8A8)[i] >> 3;
BYTE Alpha = ((PBYTE)B8G8R8A8)[i + 3];

uint16_t RGB565 = ((Red >> 3) << 11) | ((Green >> 2) << 5) | (Blue >> 3);

R5G5B5[j] = RGB565 >> 8;
R5G5B5[j + 1] = RGB565 & 0xFF;
j = j + 2;
}
}

void WriteDataToBmp(const WCHAR *filename, void *imageData, int width, int height, int BitCount, int bytesPerPixel)
{
HANDLE hdl = INVALID_HANDLE_VALUE;
DWORD bytesWritten;
BITMAPFILEHEADER fileHeader;
BITMAPINFOHEADER fileInfo;

fileInfo.biSize = sizeof(BITMAPINFOHEADER);
fileInfo.biBitCount = BitCount;
fileInfo.biCompression = BI_RGB;
fileInfo.biWidth = width;
fileInfo.biHeight = 0 - height;
fileInfo.biPlanes = 1;
fileInfo.biSizeImage = (width * height * bytesPerPixel);

fileHeader.bfSize = sizeof(BITMAPFILEHEADER) + sizeof(BITMAPINFOHEADER) + fileInfo.biSizeImage;
fileHeader.bfType = 'MB';
fileHeader.bfOffBits = sizeof(BITMAPFILEHEADER) + sizeof(BITMAPINFOHEADER);

hdl = CreateFile(filename, GENERIC_WRITE, 0, NULL, CREATE_ALWAYS, 0, NULL);

if (hdl == INVALID_HANDLE_VALUE)
{
return;
}

WriteFile(hdl, &fileHeader, sizeof(fileHeader), &bytesWritten, NULL);
WriteFile(hdl, &fileInfo, sizeof(fileInfo), &bytesWritten, NULL);
WriteFile(hdl, imageData, fileInfo.biSizeImage, &bytesWritten, NULL);

CloseHandle(hdl);
}

unsigned char* ReadDataFromBmp(char* filename)
{
FILE* f = fopen(filename, "rb");
unsigned char info[54];
fread(info, sizeof(unsigned char), 54, f);
int width = *(int*)&info[18];
int height = *(int*)&info[22];

int size = abs(4 * width * height);
unsigned char* data = new unsigned char[size];
fread(data, sizeof(unsigned char), size, f);
fclose(f);
return data;
}

int main(int args, char** cat) {

int width = 1440;
int height = 900;

int bytesOnPixel;
BYTE *OutputImage24Bit = new BYTE[width * height * 3];
BYTE *OutputImage16Bit = new BYTE[width * height * 2];
unsigned char* inputImage32Bit = ReadDataFromBmp((char*)"E:/TestImage.bmp");

bytesOnPixel = 2;
Convert32to16(inputImage32Bit, OutputImage16Bit, width, height);
WriteDataToBmp(L"E:/TestImage16bit.bmp", OutputImage16Bit, width, height, 8 * bytesOnPixel, bytesOnPixel);

bytesOnPixel = 3;
Convert32to24(inputImage32Bit, OutputImage24Bit, width, height);
WriteDataToBmp(L"E:/TestImage24bit.bmp", OutputImage24Bit, width, height, 8 * bytesOnPixel, bytesOnPixel);
return 1;
}

最佳答案

fileInfo.biCompression = BI_RGB;



16位位图使用 BI_BITFIELDS压缩。另外,16位位图必须填充颜色表以显示它是使用555格式,565格式还是其他格式。

24位和16位位图需要填充。但是,如果以字节为单位的宽度是4的倍数,那么这不是问题。通常,您无法逐像素读取/写入像素,因为填充会丢弃所有内容。而是使2个循环遍历高度和宽度。像素大小也将取决于填充。

请注意,您可以使用或GDI +或WIC进行相同的操作。您可以将位图更改为不同的格式 PixelFormat16bppRGB555, PixelFormat16bppRGB565, PixelFormat16bppARGB1555, PixelFormat24bppRGB...
GDI +示例:
int main()
{
Gdiplus::GdiplusStartupInput tmp;
ULONG_PTR token;
Gdiplus::GdiplusStartup(&token, &tmp, NULL);

auto *source = Gdiplus::Bitmap::FromFile(L"test.bmp");
auto *destination = source->Clone(0, 0, source->GetWidth(), source->GetHeight(),
PixelFormat16bppRGB565);

CLSID clsid_bmp;
CLSIDFromString(L"{557cf400-1a04-11d3-9a73-0000f81ef32e}", &clsid_bmp);
destination->Save(L"copy.bmp", &clsid_bmp);
delete destination;
delete source;

Gdiplus::GdiplusShutdown(token);
return 0;
}

自制版本:(将 std::vector用作内存,而不是 new/delete)
void Convert32to24(const wchar_t* file, std::vector<BYTE> &src, int width, int height)
{
int width_in_bytes_32 = width * 4;
int width_in_bytes_24 = ((width * 24 + 31) / 32) * 4;
DWORD size = width_in_bytes_24 * height;
std::vector<BYTE> dst(size);

for(int h = 0; h < height; h++)
for(int w = 0; w < width; w++)
{
int i = h * width_in_bytes_32 + w * 4;
int j = h * width_in_bytes_24 + w * 3;
dst[j + 0] = src[i + 0];
dst[j + 1] = src[i + 1];
dst[j + 2] = src[i + 2];
}

BITMAPFILEHEADER bf = { 'MB', 54 + size, 0, 0, 54 };
BITMAPINFOHEADER bi = { sizeof(bi), width, height, 1, 24, BI_RGB };
std::ofstream fout(file, std::ios::binary);
fout.write((char*)&bf, sizeof(bf));
fout.write((char*)&bi, sizeof(bi));
fout.write((char*)&dst[0], size);
}

void Convert32to16(const wchar_t* file, std::vector<BYTE> &src, int width, int height)
{
int width_in_bytes_32 = width * 4;
int width_in_bytes_16 = ((width * 16 + 31) / 32) * 4;
DWORD size = width_in_bytes_16 * height;
std::vector<BYTE> dst(size);

for(int h = 0; h < height; h++)
for(int w = 0; w < width; w++)
{
int i = h * width_in_bytes_32 + w * 4;
int j = h * width_in_bytes_16 + w * 2;

//555 format, each color is from 0 to 32, instead of 0 to 256
uint16_t blu = (uint16_t)(src[i + 0] * 31.f / 255.f);
uint16_t grn = (uint16_t)(src[i + 1] * 31.f / 255.f);
uint16_t red = (uint16_t)(src[i + 2] * 31.f / 255.f);
uint16_t sum = (red) | (grn << 5) | (blu << 10);
memcpy(&dst[j], &sum, 2);
}

BITMAPFILEHEADER bf = { 'MB', 54 + size, 0, 0, 54 };
BITMAPINFOHEADER bi = { sizeof(bi), width, height, 1, 16, BI_BITFIELDS };
std::ofstream fout(file, std::ios::binary);
fout.write((char*)&bf, sizeof(bf));
fout.write((char*)&bi, sizeof(bi));

//555 format
COLORREF color[]{
0b0000000000011111,//31
0b0000001111100000,//31 << 5
0b0111110000000000 //31 << 10
};
fout.write((char*)&color, sizeof(color));
fout.write((char*)&dst[0], size);
}


int main()
{
const wchar_t* file_32 = L"E:\\TestImage.bmp";
const wchar_t* file_16 = L"E:\\OutputImage16Bit.bmp";
const wchar_t* file_24 = L"E:\\OutputImage24Bit.bmp";

BITMAPFILEHEADER bh;
BITMAPINFOHEADER bi;
std::ifstream fin(file_32, std::ios::binary);
if(!fin)
return 0;
fin.read((char*)&bh, sizeof(bh));
fin.read((char*)&bi, sizeof(bi));
if(bi.biBitCount != 32)
return 0;
std::vector<BYTE> source(bh.bfSize);
fin.read((char*)&source[0], bh.bfSize);
Convert32to16(file_16, source, bi.biWidth, bi.biHeight);
Convert32to24(file_24, source, bi.biWidth, bi.biHeight);
return 0;
}

关于windows - C++将32位bmp图像转换为24位bmp和16位bmp,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/51430619/

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