windows - 如何在输出中获取输入基名？

Question

@echo off
set source="%1"

for %%a in (*.wav, *.aac, *.mp3,) do (
    ffmpeg -i "%1" -i "%%a" -c:v copy -map 0:v:0 -map 1:a:0 -shortest "%1_123.mov"
  )

我得到了 DJI_0002.MOV_123.mov，但我需要得到 DJI_0002_123.mov。

Answer 1

@echo off
set source="%1"

for %%a in (*.wav, *.aac, *.mp3,) do (
    ffmpeg -i "%1" -i "%%a" -c:v copy -map 0:v:0 -map 1:a:0 -shortest "%~n1_123.mov"
  )

~n 将替换扩展为仅等于文件名，减去扩展名。 https://docs.microsoft.com/en-us/previous-versions/windows/it-pro/windows-xp/bb490909(v=technet.10)