django - 向路由器或 View 集添加更多 View (Django-Rest-Framework)

Question

从本质上讲，我试图找到一种在不创建自定义路由器的情况下将更多 View 附加到路由器的好方法。 有什么好方法可以实现这一点？

这有点类似于我想要完成的事情。为了这个问题，变量名称已更改，并且我要介绍的示例方法非常简化。

路由器:

router = routers.SimpleRouter(trailing_slash=False)
router.register(r'myobjects', MyObjectViewSet, base_name='myobjects')
urlpatterns = router.urls

View 集

class MyObjectsViewSet(viewsets.ViewSet):
""" Provides API Methods to manage MyObjects. """

def list(self, request):
    """ Returns a list of MyObjects. """
    data = get_list_of_myobjects()
    return Response(data)

def retrieve(self, request, pk):
    """ Returns a single MyObject. """
    data = fetch_my_object(pk)
    return Response(data)

def destroy(self, request, pk):
    """ Deletes a single MyObject. """
    fetch_my_object_and_delete(pk)
            return Response()

我需要包括的另一种方法类型的一个示例。 (有很多这样的):

def get_locations(self, request):
    """ Returns a list of location objects somehow related to MyObject """
    locations = calculate_something()
    return Response(locations)

最终结果是以下 URL 将正常工作并“干净地”实现。

GET example.com/myobjects/123/locations

Answer 1

answer given by mariodev以上是正确的，只要您只想制作 GET要求。

如果您想 POST对于要附加到 ViewSet 的函数，您需要使用 action装饰器:

from rest_framework.decorators import action, link
from rest_framework.response import Response

class MyObjectsViewSet(viewsets.ViewSet):

    # For GET Requests
    @link()
    def get_locations(self, request):
        """ Returns a list of location objects somehow related to MyObject """
        locations = calculate_something()
        return Response(locations)

    # For POST Requests
    @action()
    def update_location(self, request, pk):
        """ Updates the object identified by the pk """
        location = self.get_object()
        location.field = update_location_field() # your custom code
        location.save()

        # ...create a serializer and return with updated data...

那么你会 POST到格式如下的 URL: /myobjects/123/update_location/
http://www.django-rest-framework.org/api-guide/viewsets/#marking-extra-actions-for-routing如果您有兴趣，可以提供更多信息!