wpf - 使用comboBox作为源将自动生成的DataGrid分组

Question

ViewModel :
我想选择所有Persons(每个人都可以是Type:Employee，Manager或Customer ，是PersonType 中存在的Persons的不同集合)
这是我要让ViewModel进行的唯一操作。

View :
我想要一个ComboBox的PersonTypes和一个基于所选DataGrid的PersonType(换句话说，Id喜欢让ComboBox负责ComboBox DataGrid)过滤的Grouping，并且将在XAML中完成所有操作。

有什么建议？

谢谢你。

Answer 1

    <Grid>
    <Grid.RowDefinitions>
        <RowDefinition Height="50"/>
        <RowDefinition Height="250"/>
    </Grid.RowDefinitions>
    <Grid.ColumnDefinitions>
        <ColumnDefinition Width="200"/>
        </Grid.ColumnDefinitions>
    <ComboBox x:Name="combo" ItemsSource="{Binding PersonTypes}" Tag="{Binding Persons}"/>
    <DataGrid  Grid.Row="1" AutoGenerateColumns="False">
        <DataGrid.ItemsSource>
            <MultiBinding Converter="{StaticResource conv}">
                <Binding Path="Tag" ElementName="combo"/>
                <Binding Path="SelectedItem" ElementName="combo"/>
            </MultiBinding>
        </DataGrid.ItemsSource>
        <DataGrid.Columns>
            <DataGridTextColumn Binding="{Binding Name}"/>
        </DataGrid.Columns>
    </DataGrid>

</Grid>

    public partial class MainWindow : Window
{
    public MainWindow()
    {
        InitializeComponent();
        DataContext = new ViewModel();
    }
}
public class ViewModel
{
    public ViewModel()
    {
        PersonTypes = new ObservableCollection<PersonType>() { PersonType.Manager, PersonType.Customer, PersonType.Employee };

        Persons = new ObservableCollection<Person>();
        Persons.Add(new Person() { Name = "ABC", Type = PersonType.Manager });
        Persons.Add(new Person() { Name = "DEF", Type = PersonType.Manager });
        Persons.Add(new Person() { Name = "GHI", Type = PersonType.Customer });
        Persons.Add(new Person() { Name = "JKL", Type = PersonType.Manager });
        Persons.Add(new Person() { Name = "MNO", Type = PersonType.Employee });
    }
    public ObservableCollection<Person> Persons { get; set; }
    public ObservableCollection<PersonType> PersonTypes { get; set; }

}
public class Person
{
    public string Name { get; set; }
    public PersonType Type { get; set; }
}

public enum PersonType
{
    Manager = 0,
    Employee = 1,
    Customer = 2
}
public class MyConverter : IMultiValueConverter
{
    public object Convert(object[] values, Type targetType, object parameter, System.Globalization.CultureInfo culture)
    {
        if (values.Count() > 1 && values[1] !=null && values[0] is ObservableCollection<Person>)
        {
            string ptype = values[1].ToString();
            ObservableCollection<Person> persons = (ObservableCollection<Person>)values[0];
            if (ptype != null && persons != null)
            {
                return persons.Where(p => p.Type.ToString() == ptype).ToList();
            }
        }

        return null;
    }

    public object[] ConvertBack(object value, Type[] targetTypes, object parameter, System.Globalization.CultureInfo culture)
    {
        throw new NotImplementedException();
    }
}

我希望这将有所帮助。