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javascript - 未捕获的无效状态错误 : Failed to execute 'send' on 'WebSocket' :

转载 作者:行者123 更新时间:2023-12-03 10:32:09 26 4
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我正在尝试运行此代码:

function smConnect() {
ws = new WebSocket('ws://127.0.0.1:1805/');
delete ws.URL;

ws.onopen = function(response) {};
ws.onmessage = function(response) {};
ws.onclose = function(response) {};
ws.onerror = function(error) {};
}

smConnect();
ws.send('message', 'hi');

但它返回给我这个错误:

Uncaught InvalidStateError: Failed to execute 'send' on 'WebSocket': Still in CONNECTING state.

可能是什么问题?

最佳答案

你可以这样做,它添加了一些日志记录,发送你可以在构造函数之外处理的信息,并且你还可以在它自己的命名空间中抽象出 SocketWrapper (好吧,是的,它现在在窗口中:))

您可以检查开发工具(大多数浏览器中的 F12)以查看日志/错误中发生的情况,例如:这里抛出错误,因为没有可用的套接字:)

并且您不需要为所有事件提供值,只需为您需要的事件提供值(您的情况是 onopen + 也许是 onmessage?)

(在定义的回调中,这将指向套接字,而不是 SocketWrapper,SocketWrapper 也不提供 ws 变量,它是私有(private)的,但我猜应该这样做)

SocketWrapper 上有一个发送方法,当您发送到一个关闭的流时,它会抛出一个错误,但如果它尚未打开,它会将消息排队直到它被打开,然后清空队列以websocket(所以从某种意义上说,您不需要设置 onopen 回调,只需使用 send 方法添加它就可以了;)

(function(nameSpace) {
function createMethod(method, options, stateCallback) {
var that = this;
this[method] = function() {
if (stateCallback && stateCallback.apply) {
stateCallback(method);
}
console.info(method);
if (options[method] && options[method].apply) {
options[method].apply(that, arguments);
}
};
}

function SocketWrapper(options) {
var ws,
events = ['onopen', 'onmessage', 'onclose', 'onerror'],
i, len, prop = {
opened: false,
closed: false,
error: false
},
method;

if (typeof options === 'undefined' || !options) {
throw 'ArgumentException: please add default constructor options';
}

this.queue = [];

this.onEventTrigger = function(eventName) {
var i, len;
if (eventName === 'onopen') {
prop.opened = true;
prop.closed = false;
// openend send queue
if (this.queue.length > 0) {
for (i = this.queue.length; --i >= 0;) {
this.send.apply(this, this.queue[0]);
this.queue.splice(0, 1);
}
}
}
if (eventName === 'onerror') {
prop.error = true;
}
if (eventName === 'onclosed') {
prop.opened = false;
prop.closed = true;
}
};

this.init = function() {
var cb = this.onEventTrigger.bind(this);
ws = new WebSocket(options.url);

for (i = 0; i < events.length; i++) {
method = events[i];
createMethod.apply(ws, [method, options, cb]);
}
};

this.send = function() {
if (prop.closed) {
throw 'InvalidOperation: Cannot send messages to a closed Websocket!';
}
if (!prop.opened) {
this.queue.push(arguments);
} else {
ws.send.apply(ws, arguments);
}
};

this.init();
return this;
}

window.SocketWrapper = SocketWrapper;
}(window));

var socket = new window.SocketWrapper({
url: 'ws://127.0.0.1:1805',
onopen: function() {
this.send('message', 'hi');
},
onmessage: function() {
console.log(arguments);
},
onclose: function() {
socket = null;
},
onerror: function() {
console.log('error occured, oh no!');
console.error(arguments);
}
});
socket.send('i am message send to soon, but since i check the state of the ws object, i will be queued and send when appropriate');

关于javascript - 未捕获的无效状态错误 : Failed to execute 'send' on 'WebSocket' :,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29157807/

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