web-services - CXF 网络服务客户端 : "Cannot create a secure XMLInputFactory"

Question

我使用说明 here 编写了一个 CXF Web 服务并将其部署到 Tomcat 服务器中。 . Web 服务部署良好，因为我可以在 Web 浏览器中看到 WSDL 文件。

但我的独立 Java 客户端程序不起作用。这是代码:

System.out.println("Creating client");
Properties properties = System.getProperties();
properties.put("org.apache.cxf.stax.allowInsecureParser", "1");
System.setProperties(properties);
JaxWsProxyFactoryBean factory = new JaxWsProxyFactoryBean();
factory.setServiceClass(ExampleWebService.class);
factory.setAddress("http://X.X.X.X:9090/WebServices/ExampleWebService");
ExampleWebService exampleWebService = (ExampleWebService)factory.create();
System.out.println("Done creating client");
exampleWebService.method1("test");
System.out.println("After calling method1");

我将 CXF 2.7.7 发行版中的所有 jar 文件(包括 woodstox-core-asl-4.2.0.jar 文件)复制到客户端程序的类路径中，当我运行客户端时，出现以下异常:

Creating client
Nov 20, 2013 8:05:26 PM org.apache.cxf.service.factory.ReflectionServiceFactoryBean buildServiceFromClass
INFO: Creating Service {http://webservices.server/}ExampleWebServiceService from class server.webservices.ExampleWebService
Done creating client
javax.xml.ws.soap.SOAPFaultException: Cannot create a secure XMLInputFactory
    at org.apache.cxf.jaxws.JaxWsClientProxy.invoke(JaxWsClientProxy.java:157)
    at $Proxy38.printString(Unknown Source)
    at ExampleNmsWebServiceClient.printString(ExampleNmsWebServiceClient.java:29)
    at ExampleNmsWebServiceClient.main(ExampleNmsWebServiceClient.java:40)
Caused by: org.apache.cxf.binding.soap.SoapFault: Cannot create a secure XMLInputFactory
    at org.apache.cxf.binding.soap.interceptor.Soap11FaultInInterceptor.unmarshalFault(Soap11FaultInInterceptor.java:84)
    at org.apache.cxf.binding.soap.interceptor.Soap11FaultInInterceptor.handleMessage(Soap11FaultInInterceptor.java:51)
    at org.apache.cxf.binding.soap.interceptor.Soap11FaultInInterceptor.handleMessage(Soap11FaultInInterceptor.java:40)
    at org.apache.cxf.phase.PhaseInterceptorChain.doIntercept(PhaseInterceptorChain.java:272)
    at org.apache.cxf.interceptor.AbstractFaultChainInitiatorObserver.onMessage(AbstractFaultChainInitiatorObserver.java:113)
    at org.apache.cxf.binding.soap.interceptor.CheckFaultInterceptor.handleMessage(CheckFaultInterceptor.java:69)
    at org.apache.cxf.binding.soap.interceptor.CheckFaultInterceptor.handleMessage(CheckFaultInterceptor.java:34)
    at org.apache.cxf.phase.PhaseInterceptorChain.doIntercept(PhaseInterceptorChain.java:272)
    at org.apache.cxf.endpoint.ClientImpl.onMessage(ClientImpl.java:835)
    at org.apache.cxf.transport.http.HTTPConduit$WrappedOutputStream.handleResponseInternal(HTTPConduit.java:1606)
    at org.apache.cxf.transport.http.HTTPConduit$WrappedOutputStream.handleResponse(HTTPConduit.java:1502)
    at org.apache.cxf.transport.http.HTTPConduit$WrappedOutputStream.close(HTTPConduit.java:1309)
    at org.apache.cxf.transport.AbstractConduit.close(AbstractConduit.java:56)
    at org.apache.cxf.transport.http.HTTPConduit.close(HTTPConduit.java:627)
    at org.apache.cxf.interceptor.MessageSenderInterceptor$MessageSenderEndingInterceptor.handleMessage(MessageSenderInterceptor.java:62)
    at org.apache.cxf.phase.PhaseInterceptorChain.doIntercept(PhaseInterceptorChain.java:272)
    at org.apache.cxf.endpoint.ClientImpl.doInvoke(ClientImpl.java:565)
    at org.apache.cxf.endpoint.ClientImpl.invoke(ClientImpl.java:474)
    at org.apache.cxf.endpoint.ClientImpl.invoke(ClientImpl.java:377)
    at org.apache.cxf.endpoint.ClientImpl.invoke(ClientImpl.java:330)
    at org.apache.cxf.frontend.ClientProxy.invokeSync(ClientProxy.java:96)
    at org.apache.cxf.jaxws.JaxWsClientProxy.invoke(JaxWsClientProxy.java:135)
    ... 3 more

我发现一个页面说“无法创建安全的 XMLInputFactory”可以通过将 org.apache.cxf.stax.allowInsecureParser 属性设置为“1”来修复，这就是我尝试在系统属性中设置它的原因，但没有不行。我还尝试将 -Dorg.apache.cxf.stax.allowInsecureParser=1 添加到运行客户端的 java 命令中，但这也不起作用。 (也没有将其设置为“true”而不是 1。)有关如何解决此错误的任何想法？

Answer 1

从 CXF 2.3.x 升级到 2.7.x 时出现此问题

已添加 stax2-api 和 woodstox-core-asl 来自 2.7.x CXF 发行版的 jars 和 webservice 再次工作。