javascript - 或者条件永远不会计算为 true

Question

这段 JavaScript 代码成功运行，但我认为它没有通过“else”语句，因为它没有打印其控制台......为什么？

 i = 0;
    for(var i=1; i<4; i++) {
    var crazy = prompt("would you marry me?");
         if(crazy === "Yes"|| "yes") {
           console.log("hell ya!");
       }
     /* when it asks "will you marry me" and if the user says either "No" or      "no", it does't print "ok..I'' try again next time". instead, it still says "hell ya !" */
     else if (crazy ==="No" ||"no") {
       console.log("ok..I'll try again next time !");
   }
}
var love = false;
do {
      console.log("nonetheless, I LOVE YOU !");
}
while(love);

Answer 1

尝试这样的事情，

 if(crazy.toUpperCase() === "YES") {
    console.log("hell ya!");
 }