linux - 如何检查BASH中的文件？

Question

我正在为学校写BASH。 Shell脚本应搜索任何名为'file'的文本文件，文件末尾的数字应为1-10。程序回显说每个文件是否存在。

但是，我只是无法让该程序搜索文件。

我做了一个递增一的数字。我找不到将此变量放在"file"和“.txt”之间的方法。我能做些什么？

#!/bin/sh
number=1
x=$(grep file<$number>.txt)
((number++))
while [ $number -le 10 ]
do
    if [ $x -eq true ]
    then
        echo file<$number>.txt exists
    else
        echo file<$number>.txt does not exist
    fi
    ((number++))
done

Answer 1

使用bash:

$ touch file3.txt
$ for i in {1..10}; do file="file${i}.txt"; [[ -f $file ]] && echo "$file exists" || echo "$file doesn't exist"; done
file1.txt doesn't exist
file2.txt doesn't exist
file3.txt exists
file4.txt doesn't exist
file5.txt doesn't exist
file6.txt doesn't exist
file7.txt doesn't exist
file8.txt doesn't exist
file9.txt doesn't exist
file10.txt doesn't exist

使用 sh:

$ for i in `seq 1 10`; do file="file${i}.txt"; if [ -f "$file" ]; then echo "$file exists"; else echo "$file doesn't exist"; fi; done
file1.txt doesn't exist
file2.txt doesn't exist
file3.txt exists
file4.txt doesn't exist
file5.txt doesn't exist
file6.txt doesn't exist
file7.txt doesn't exist
file8.txt doesn't exist
file9.txt doesn't exist
file10.txt doesn't exist