javascript - 将值添加到 y :axis if all the values are Zero after filtering

Question

有一个 JavaScript 可以删除重复的标签 label:'Adnim' 并通过跳过零“0”y 仅计数“1”y:1, :0， 这是工作完美，但问题是，如果特定标签的所有值都为零，那么对于该标签，它不会给出任何输出。

示例:1

       {y:0,label:'Adnim'},
       {y:0,label:'Adnim'},
        {y:0,label:'Adnim'},
        {y:1,label:'Adnim'},//Value of y:1  is one all are zero 
      {y:0,label:'Adnim2'},
     {y:0,label:'Adnim2'},
       {y:1,label:'Adnim2'},
      {y:1,label:'Adnim2'},

当前输出:

      {y:1,label:'Adnim'},
      {y:2,label:'Adnim2'},

示例:2

       {y:0,label:'Adnim'},
       {y:0,label:'Adnim'},
        {y:0,label:'Adnim'},
        {y:0,label:'Adnim'},//Value of y:0  is all are zero 
      {y:0,label:'Adnim2'},
     {y:0,label:'Adnim2'},
       {y:1,label:'Adnim2'},
      {y:1,label:'Adnim2'},

当前输出:

      {y:2,label:'Adnim2'},

预期输出:

     {y:0,label:'Adnim'},
      {y:2,label:'Adnim2'},

JavaScript:

 var list = [
  {y:0,label:'Adnim'},
   {y:0,label:'Adnim'},
    {y:0,label:'Adnim'},
    {y:1,label:'Adnim'},
  {y:0,label:'Adnim2'},
 {y:0,label:'Adnim2'},
   {y:1,label:'Adnim2'},
  {y:1,label:'Adnim2'},
]

var counters = {}
var result = [];
var resultString = '';
var label;

list.forEach(function(el){
    label = el.label;
    // Skip zero y's
    if (el.y === 0) return;

    // Increase counter values
    if (counters.hasOwnProperty(label)) {
        counters[label] += 1;
    } else {
        counters[label] = 1;
    }
});

// Convert counters object to array of objects
for (var label in counters) {
    result.push({'label': label, 'y': counters[label]});
}

// Render result to the target div
console.log(result);

result = result.map(function(el){ return '{y: ' + el.y + ', label: "' + el.label + '"}' });
resultString = '[' + result.join(', ') + ']';
$('#target').html(resultString);

Answer 1

当没有 y==0 的项目时，您永远不会创建计数器条目。尝试使用以下替换 forEach 函数(在 Chrome 中测试):

list.forEach(function(el) {
    label = el.label;

    // Init the counters entry if necessary
    if (!counters.hasOwnProperty(label)) 
        counters[label] = 0;

    if (el.y !== 0)
        counters[label] += 1;
});