php - phpMyAdmin DisplayResults.php＃1226中的错误

Question

IAM试图显示phpmyadmin中的所有记录，phpmyadmin给出警告
当我尝试在PHPMyAdmin上访问数据库中的表时，似乎全部使PHPMyAdmin崩溃。

我无法在线找到解决方案，请寻求您的帮助

我有一个我无法解决的问题，错误。./libraries/DisplayResults.php＃1226 中的通知

    Notice in ./libraries/DisplayResults.php#1226
 Trying to access array offset on value of type bool

Backtrace

./libraries/DisplayResults.php#1346: PMA\libraries\DisplayResults->_getTableHeadersForColumns(
array,
array,
array,
array,
array,
boolean false,
string 'SELECT * FROM `wp_options` ',
)
./libraries/DisplayResults.php#4424: PMA\libraries\DisplayResults->_getTableHeaders(
array,
array,
string 'SELECT * FROM `wp_options` ',
array,
array,
array,
boolean false,
)
./libraries/sql.lib.php#1686: PMA\libraries\DisplayResults->getTable(
,
array,
array,
boolean false,
)
./libraries/sql.lib.php#1980: PMA_getHtmlForSqlQueryResultsTable(
,
string './themes/pmahomme/img/',
NULL,
array,
boolean true,
string '137',
integer 25,
NULL,
,
array,
)
./libraries/sql.lib.php#2199: PMA_getQueryResponseForResultsReturned(
,
array,
string 'dbcc',
string 'wp_options',
NULL,
NULL,
,
string './themes/pmahomme/img/',
string '137',
integer 25,
NULL,
NULL,
NULL,
NULL,
NULL,
string 'SELECT * FROM `wp_options`',
NULL,
)
./libraries/sql.lib.php#2062: PMA_executeQueryAndGetQueryResponse(
array,
boolean true,
string 'dbcc',
string 'wp_options',
NULL,
NULL,
NULL,
NULL,
NULL,
NULL,
string '',
string './themes/pmahomme/img/',
NULL,
NULL,
NULL,
string 'SELECT * FROM `wp_options`',
NULL,
NULL,
)
./sql.php#221: PMA_executeQueryAndSendQueryResponse(
array,
boolean true,
string 'dbcc',
string 'wp_options',
NULL,
NULL,
NULL,
NULL,
NULL,
NULL,
string '',
string './themes/pmahomme/img/',
NULL,
NULL,
NULL,
string 'SELECT * FROM `wp_options`',
NULL,
NULL,
)

Answer 1

我解决了这个
在我的代码中，在1233行中包含:

list($order_link, $sorted_header_html)
    = $this->_getOrderLinkAndSortedHeaderHtml(
        $fields_meta[$i], $sort_expression,
        $sort_expression_nodirection, $i, $unsorted_sql_query,
        $session_max_rows, $comments,
        $sort_direction, $col_visib,
        $col_visib[$j]
    );

我插入了一个新的“isset”验证，例如:

$check = (isset($col_visib[$j])) ? $col_visib[$j] : false;

但是在条件下使用..

list($order_link, $sorted_header_html)
    = $this->_getOrderLinkAndSortedHeaderHtml(
        $fields_meta[$i], $sort_expression,
        $sort_expression_nodirection, $i, $unsorted_sql_query,
        $session_max_rows, $comments,
        $sort_direction, $col_visib,
        isset($col_visib[$j]) ? $col_visib[$j] : false
    );

@编辑
使用高于7.2的php。我们可以改变

isset($col_visib[$j]) ? $col_visib[$j] : false

为了

col_visib[$j] ?? false

然后..

list($order_link, $sorted_header_html)
    = $this->_getOrderLinkAndSortedHeaderHtml(
        $fields_meta[$i], $sort_expression,
        $sort_expression_nodirection, $i, $unsorted_sql_query,
        $session_max_rows, $comments,
        $sort_direction, $col_visib,
        $col_visib[$j] ?? false
    );