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spring-mvc - 没有可用于当前线程的实际事务的 EntityManager - 无法可靠地处理 'persist' 调用

转载 作者:行者123 更新时间:2023-12-03 09:49:36 26 4
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没有可用于当前线程的实际事务的 EntityManager - 无法可靠地处理“持久”调用

当我使用 JUnit 进行测试时,persist 方法有效并且我看到我的对象已插入,但是当我通过我的 Controller 调用该方法时不起作用

这是我的项目:

应用上下文.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xmlns:tx="http://www.springframework.org/schema/tx"
xmlns:mvc="http://www.springframework.org/schema/mvc"
xmlns:util="http://www.springframework.org/schema/util"
xmlns:task="http://www.springframework.org/schema/task"
xsi:schemaLocation="http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-4.2.xsd
http://www.springframework.org/schema/task http://www.springframework.org/schema/task/spring-task-4.2.xsd
http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-4.2.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx-4.1.xsd
http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util-4.2.xsd">



<!-- <bean id="notification" class="com.app.sqli.notification.NotificationTask" /> -->

<!-- <task:scheduled-tasks> -->
<!-- <task:scheduled ref="notification" method="notifier" cron="*/2 * * * * *"/> -->
<!-- </task:scheduled-tasks> -->

<context:component-scan base-package="com.app.sqli" />

<mvc:annotation-driven />
<bean id="entityManagerFactoryBean" class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
<property name="dataSource" ref="dataSource" />
<property name="packagesToScan" value="com.app.sqli.entities" />
<property name="jpaVendorAdapter">
<bean class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter" />
</property>
<property name="jpaProperties">
<props>
<prop key="hibernate.hbm2ddl.auto">validate</prop>
<prop key="hibernate.dialect">org.hibernate.dialect.MySQL5Dialect</prop>
</props>
</property>
</bean>


<bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource">
<property name="driverClassName" value="com.mysql.jdbc.Driver" />
<property name="url" value="jdbc:mysql://localhost:3306/sqli" />
<property name="username" value="root" />
<property name="password" value="" />
</bean>


<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="entityManagerFactoryBean" />
</bean>


<tx:annotation-driven />


</beans>

我的模型类:
package com.app.sqli.models;

import javax.persistence.Entity;
import javax.persistence.Id;

@Entity
public class Collaborateur {

@Id
private int id;
private String nom;

public int getId() {
return id;
}

public void setId(int id) {
this.id = id;
}

public String getNom() {
return nom;
}

public void setNom(String nom) {
this.nom = nom;
}

}

我的 DAO 类
package com.app.sqli.dao;

import javax.persistence.EntityManager;
import javax.persistence.PersistenceContext;

import org.springframework.stereotype.Repository;

import com.app.sqli.models.Collaborateur;

@Repository
public class CollaborateurDao implements IcollaborateurDao{

@PersistenceContext
private EntityManager em;

@Override
public void addCollaborateur(Collaborateur c) {
em.persist(c);

}

}

我的服务类
package com.app.sqli.services;

import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Service;
import org.springframework.transaction.annotation.Transactional;

import com.app.sqli.dao.IcollaborateurDao;
import com.app.sqli.models.Collaborateur;

@Service
@Transactional
public class CollaborateurService implements IcollaborateurService{

@Autowired
private IcollaborateurDao cdao;

@Override
public void addCollaborateur(Collaborateur c) {
cdao.addCollaborateur(c);

}


}

和我的 Controller
package com.app.sqli.controller;

import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.ui.Model;
import org.springframework.web.bind.annotation.RequestMapping;

import com.app.sqli.models.Collaborateur;
import com.app.sqli.services.IcollaborateurService;

@org.springframework.stereotype.Controller
public class Controller {
@Autowired
private IcollaborateurService cserv;

@RequestMapping(value = "/index")
public String index(Model m) {
System.out.println("insertion ...");
Collaborateur c = new Collaborateur();
c.setId(11);
c.setNom("nom");
cserv.addCollaborateur(c);
return "index";
}

}

最佳答案

谢谢@mechkov 的时间和帮助,
我的问题是通过更改我的配置文件解决的,所以我使用了一个带有注释的配置类并且它的工作非常好,我仍然不知道问题出在哪里

    @Configuration
@ComponentScan(basePackages = "your package")
@EnableTransactionManagement
public class DatabaseConfig {

protected static final String PROPERTY_NAME_DATABASE_DRIVER = "com.mysql.jdbc.Driver";
protected static final String PROPERTY_NAME_DATABASE_PASSWORD = "password";
protected static final String PROPERTY_NAME_DATABASE_URL = "jdbc:mysql://localhost:3306/databasename";
protected static final String PROPERTY_NAME_DATABASE_USERNAME = "login";

private static final String PROPERTY_PACKAGES_TO_SCAN = "where your models are";
@Bean
public LocalContainerEntityManagerFactoryBean entityManagerFactoryBean(DataSource dataSource, JpaVendorAdapter jpaVendorAdapter){
LocalContainerEntityManagerFactoryBean entityManagerFactoryBean = new LocalContainerEntityManagerFactoryBean();
entityManagerFactoryBean.setDataSource(dataSource);
entityManagerFactoryBean.setJpaVendorAdapter(jpaVendorAdapter);
entityManagerFactoryBean.setPackagesToScan(PROPERTY_PACKAGES_TO_SCAN);
return entityManagerFactoryBean;
}

@Bean
public BasicDataSource dataSource(){
BasicDataSource ds = new BasicDataSource();
ds.setDriverClassName(PROPERTY_NAME_DATABASE_DRIVER);
ds.setUrl(PROPERTY_NAME_DATABASE_URL);
ds.setUsername(PROPERTY_NAME_DATABASE_USERNAME);
ds.setPassword(PROPERTY_NAME_DATABASE_PASSWORD);
ds.setInitialSize(5);
return ds;
}

@Bean
public JpaVendorAdapter jpaVendorAdapter(){
HibernateJpaVendorAdapter adapter = new HibernateJpaVendorAdapter();
adapter.setDatabase(Database.MYSQL);
adapter.setShowSql(true);
adapter.setGenerateDdl(true);

//I'm using MySQL5InnoDBDialect to make my tables support foreign keys
adapter.setDatabasePlatform("org.hibernate.dialect.MySQL5InnoDBDialect");
return adapter;
}

@Bean
public PlatformTransactionManager transactionManager(EntityManagerFactory entityManagerFactory) {
return new JpaTransactionManager(entityManagerFactory);
}


}

关于spring-mvc - 没有可用于当前线程的实际事务的 EntityManager - 无法可靠地处理 'persist' 调用,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/33781945/

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