javascript - 测试不同值的许多条件的干净方法？

Question

所以，我想针对不同的值测试许多条件...现在只是一堆 if,else 语句...

但它看起来很难看，我确信一定有更好的方法......

有什么想法吗？

我想也许使用循环，但是或者将所有变量放入一个数组中，但我不知道如何......

谢谢!

var dataObject = {}

if (newState.playerId){
  dataObject["filter[player_id]"] = newState.playerId
}else{
  dataObject["filter[player_id]"] = this.state.playerId
}

if (newState.pageLimit){
  dataObject ["page[limit]"] = newState.pageLimit
}else{
  dataObject["page[limit]"] = this.state.pageLimit
}

if (newState.timeFrom){
  dataObject["time[from]"] = newState.timeFrom
}else{
  dataObject["time[from]"] = this.state.timeFrom
}

if (newState.timeTo){
  dataObject["time[to]"] = newState.timeTo
}else{
  dataObject["time[to]"] = this.state.timeTo
}

if (newState.gameId){
  dataObject["filter[game_id]"] = newState.gameId
}else{
  dataObject["filter[game_id]"] = this.state.gameId
}

if (newState.customerId){
  dataObject["filter[customer_id]"] = newState.customerId
}else{
  dataObject["filter[customer_id]"] = this.state.customerId
}

if (newState.currency){
  dataObject["filter[currency]"] = newState.currency
}else{
  dataObject["filter[currency]"] = this.state.currency
}

if (newState.variant){
  dataObject["filter[locale]"] = newState.locale
}else{
  dataObject["filter[locale]"] = this.state.locale
}

if (newState.variant){
  dataObject["filter[demo]"] = newState.demo
}else{
  dataObject["filter[demo]"] = this.state.demo
}

Answer 1

使用 or (||) 运算符利用 short circuit evaluation ，例如

 dataObject["filter[player_id]"] = newState.playerId ||  this.state.playerId