javascript - 当到达某个点时计算字符数

Question

我有以下代码，运行良好；

var text_max = 459;
    var text_used = 0;
    var sms_count = 0;
    $('#leftstring').html(text_max + '');
    $('#usedstring').html(text_used + '');
    $('#sms_count').html(sms_count + '');
    $(document).on("keyup","#Message", function() {
        var text_length = $('#Message').val().length;
        var text_remaining = text_max - text_length;
        var text_completed = text_used + text_length;
        if(text_length <= 152) {
            var smscounts =+ parseInt(smscounts)+1;
        }
        $('#leftstring').html(text_remaining + '');
        $('#usedstring').html(text_completed + '');
        $('#sms_count').html(smscounts + '');
    });

问题出在 sms_count 上，因为我正在尝试的是:我有 459 个字符的限制，所以我想将其除以 3，因此当字符达到 152 时，应计为 1，然后对于下一个 152，应计为 2 code> 然后最后一个 152 应该算到 3

Answer 1

您可能可以使用 Math.ceil() 来查找必须发送的最小消息数。

var per_text = 152

$(document).on("keyup","#Message", function() {
    var text_length = $('#Message').val().length;
    var text_remaining = text_max - text_length;
    var text_completed = text_used + text_length;
    var smscounts = Math.ceil(text_length / per_text);

    $('#leftstring').html(text_remaining + '');
    $('#usedstring').html(text_completed + '');
    $('#sms_count').html(smscounts + '');
});