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openlayers - 使用 Leaflet.js 编写一个将圆转换为多边形的函数

转载 作者:行者123 更新时间:2023-12-03 09:34:12 31 4
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以下是如何在 ol2 http://jsfiddle.net/4S5Ke/166/ 中编写执行此操作的函数的示例这是一些代码:

function createGeodesicPolygon(origin, radius, sides, rotation, projection) {

if (projection.getCode() !== "EPSG:4326") {
origin.transform(projection, new OpenLayers.Projection("EPSG:4326"));
}
var latlon = new OpenLayers.LonLat(origin.x, origin.y);

var angle;
var new_lonlat, geom_point;
var points = [];

for (var i = 0; i < sides; i++) {
angle = (i * 360 / sides) + rotation;
new_lonlat = OpenLayers.Util.destinationVincenty(latlon, angle, radius);
new_lonlat.transform(new OpenLayers.Projection("EPSG:4326"), projection);
geom_point = new OpenLayers.Geometry.Point(new_lonlat.lon, new_lonlat.lat);
points.push(geom_point);
}
var ring = new OpenLayers.Geometry.LinearRing(points);
return new OpenLayers.Geometry.Polygon([ring]);

}

与 OpenLayers.Util.destinationVincenty 和 OpenLayers.Geometry.LinearRing 等函数等效的传单是什么?知道了这一点,我想我可以使用传单重写该函数以使其工作。帮助??

最佳答案

嗯..我最终做的是重写几个 OpenLayers 2 函数,以便它们可以使用 Leaflet 工作。一个函数围绕一个半径创建一个正多边形。它看起来像这样:

function createGeodesicPolygon(origin, radius, sides, rotation, projection) {
var latlon = origin; //leaflet equivalent
var angle;
var new_lonlat, geom_point;
var points = [];

for (var i = 0; i < sides; i++) {
angle = (i * 360 / sides) + rotation;
new_lonlat = destinationVincenty(latlon, angle, radius);
geom_point = L.latLng(new_lonlat.lng, new_lonlat.lat);

points.push(geom_point);
}

return points;
}

现在进行一些触发。首先,我们设置一些常量:
L.Util.VincentyConstants = {
a: 6378137,
b: 6356752.3142,
f: 1/298.257223563
};

然后我们重写 OpenLayers.Util.destinationVincenty 函数 http://dev.openlayers.org/docs/files/OpenLayers/Util-js.html#Util.destinationVincenty与传单一起工作。

参数:
lonlat -(具有 .lat 和 .lng 属性的任何对象)起点。
brng - {Float} 方位(度)。
dist - {Float} 地面距离(米)。

返回:
{L.latLng} 目的地点。

很多触发功能。不要害怕。我们只需要更改几行(感谢 John B 的想法。传单的函数看起来像这样。
function destinationVincenty(lonlat, brng, dist) { //rewritten to work with leaflet

var u = L.Util;
var ct = u.VincentyConstants;
var a = ct.a, b = ct.b, f = ct.f;
var lon1 = lonlat.lng;
var lat1 = lonlat.lat;
var s = dist;
var pi = Math.PI;
var alpha1 = brng * pi/180 ; //converts brng degrees to radius
var sinAlpha1 = Math.sin(alpha1);
var cosAlpha1 = Math.cos(alpha1);
var tanU1 = (1-f) * Math.tan( lat1 * pi/180 /* converts lat1 degrees to radius */ );
var cosU1 = 1 / Math.sqrt((1 + tanU1*tanU1)), sinU1 = tanU1*cosU1;
var sigma1 = Math.atan2(tanU1, cosAlpha1);
var sinAlpha = cosU1 * sinAlpha1;
var cosSqAlpha = 1 - sinAlpha*sinAlpha;
var uSq = cosSqAlpha * (a*a - b*b) / (b*b);
var A = 1 + uSq/16384*(4096+uSq*(-768+uSq*(320-175*uSq)));
var B = uSq/1024 * (256+uSq*(-128+uSq*(74-47*uSq)));
var sigma = s / (b*A), sigmaP = 2*Math.PI;
while (Math.abs(sigma-sigmaP) > 1e-12) {
var cos2SigmaM = Math.cos(2*sigma1 + sigma);
var sinSigma = Math.sin(sigma);
var cosSigma = Math.cos(sigma);
var deltaSigma = B*sinSigma*(cos2SigmaM+B/4*(cosSigma*(-1+2*cos2SigmaM*cos2SigmaM)-
B/6*cos2SigmaM*(-3+4*sinSigma*sinSigma)*(-3+4*cos2SigmaM*cos2SigmaM)));
sigmaP = sigma;
sigma = s / (b*A) + deltaSigma;
}
var tmp = sinU1*sinSigma - cosU1*cosSigma*cosAlpha1;
var lat2 = Math.atan2(sinU1*cosSigma + cosU1*sinSigma*cosAlpha1,
(1-f)*Math.sqrt(sinAlpha*sinAlpha + tmp*tmp));
var lambda = Math.atan2(sinSigma*sinAlpha1, cosU1*cosSigma - sinU1*sinSigma*cosAlpha1);
var C = f/16*cosSqAlpha*(4+f*(4-3*cosSqAlpha));
var lam = lambda - (1-C) * f * sinAlpha *
(sigma + C*sinSigma*(cos2SigmaM+C*cosSigma*(-1+2*cos2SigmaM*cos2SigmaM)));
var revAz = Math.atan2(sinAlpha, -tmp); // final bearing
var lamFunc = lon1 + (lam * 180/pi); //converts lam radius to degrees
var lat2a = lat2 * 180/pi; //converts lat2a radius to degrees

return L.latLng(lamFunc, lat2a);

}

由于我使用 Leaflet.Draw 来创建圆,所以我这样称呼它:
map.on('draw:created', function (e) {

var type = e.layerType,
layer = e.layer;
if (type === 'circle') {

var origin = layer.getLatLng(); //center of drawn circle
var radius = layer.getRadius(); //radius of drawn circle
var projection = L.CRS.EPSG4326;
var polys = createGeodesicPolygon(origin, radius, 60, 0, projection); //these are the points that make up the circle
var polygon = []; // store the geometry
for (var i = 0; i < polys.length; i++) {
var geometry = [polys[i].lat, polys[i].lng];
polygon.push(geometry);
}

var polyCircle = L.polygon(polygon).addTo(map); //convert geometry to a leaflet polygon and add it to the map

} else {....}

就是这样!希望能帮助到你。

关于openlayers - 使用 Leaflet.js 编写一个将圆转换为多边形的函数,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/24145205/

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