sql - 显示多条记录的第二个结果 - MSSQL2005

Question

我有一个查询，显示一位客户的第二个结果。我现在需要做的是显示特定列表中每个客户的第二个结果(例如 20 个不同的客户)。

我该怎么做？通过 SSMS 2005 的 MS SQL2000

1 位客户的当前查询是

SELECT TOP 1 link_to_client, call_ref
FROM
(
    SELECT TOP 2 link_to_client, call_ref
    FROM calls WITH (NOLOCK)
    WHERE link_to_client IN ('G/1931')
        AND call_type = 'PM'
    ORDER BY call_ref DESC
) x
ORDER BY call_ref

谢谢

Answer 1

您需要使用row_number()函数，尝试这样的事情:

select
    link_to_client, call_ref 
from
    (
        select
            link_to_client, call_ref, 
            row_number() over (partition by link_to_client order by call_ref desc) n
        from 
            calls with (nolock) 
        where 
            link_to_client in ('G/1931') 
            and call_type = 'PM' 
    ) x
where
    n = 2 -- second result for every client