php - 只想从索引中删除键而不是 php 中的值

Question

我在 php 中有数组并将其转换为 json.Now我有 json 格式的代码

{
    "2": "12:40 to 13:0",
    "3": "13:0 to 13:20",
    "4": "13:20 to 13:40",
    "5": "13:40 to 14:0",
    "6": "14:0 to 14:20",
    "7": "14:20 to 14:40",
    "8": "14:40 to 15:0",
    "9": "15:0 to 15:20",
    "10": "15:20 to 15:40",
    "11": "15:40 to 16:0",
    "12": "16:0 to 16:20",
    "13": "16:20 to 16:40",
    "14": "16:40 to 17:0",
    "15": "17:0 to 17:20",
    "16": "17:20 to 17:40",
    "17": "17:40 to 18:0"

}json 格式但我想删除索引 2,3,4,5 表单代码并希望数据位于

    {
       "12:40 to 13:0",
         "13:0 to 13:20",
        "13:20 to 13:40",
        "13:40 to 14:0",
         "14:0 to 14:20",
        "14:20 to 14:40",
        "14:40 to 15:0",
        "15:0 to 15:20",
         "15:20 to 15:40",
         "15:40 to 16:0",
         "16:0 to 16:20",
        "16:20 to 16:40",
         "16:40 to 17:0",
        "17:0 to 17:20",
         "17:20 to 17:40",
          "17:40 to 18:0"
}

任何帮助:)

Answer 1

array_values .

安authoritative资源也:

array_values($array);