javascript - 根据日期和时间显示打开或关闭

Question

我目前正在使用我在上一篇文章中找到的一些脚本..它根据日期和时间显示打开或关闭..

$(document).ready(function() {
    "use strict";
var Now = new Date();
var CurrentDay = Now.getDay();
// opening time - 24 hours so 9:30am is 9, 30
var OpeningTime = new Date(Now.getFullYear(), Now.getMonth(), Now.getDate(), 8);
// closing time - 24 hours so 5:30pm is 17, 30
var ClosingTime = new Date(Now.getFullYear(), Now.getMonth(), Now.getDate(), 20);
var Open = (Now.getTime() > OpeningTime.getTime() && Now.getTime() < ClosingTime.getTime());
// days 0.sun 1.mon 2.tues 3.wed 4.thur 5.fri 6.sat 
// CurrentDay !== 0 && the # is the day to eclude, so if I want to be closed on Sat6, Sun0, Wed3
// CurrentDay !== 6 && CurrentDay !== 0 && CurrentDay !== 3 && Open
if (CurrentDay !== 1 && CurrentDay !== 5 && Open) {
    $('.openstatus').toggle();
}
});

目前已设置为周一至周五上午 8 点至下午 8 点。但我还想在周六上午 9 点至下午 5 点和周日上午 10 点至下午 4 点之间显示开放文本

如有任何建议，我们将不胜感激。

非常感谢。

https://jsfiddle.net/xncor0b8/

Answer 1

我在这里有一个建议: https://jsfiddle.net/xncor0b8/3/

var startingHour = {
    1: 8,
    2: 8,
    3: 8,
    4: 8,    
    5: 8,        
    6: 9,
    0: 10
};
var startingMin = {
    1: 0,
    2: 0,
    3: 0,
    4: 0,    
    5: 0,        
    6: 0,
    0: 0
}

var closingHour = {
    1: 20,
    2: 20,
    3: 20,
    4: 20,    
    5: 20,        
    6: 17,
    0: 16
};

var closingMin = {
    1: 0,
    2: 0,
    3: 0,
    4: 0,    
    5: 0,        
    6: 0,
    0: 0
 };

var CurrentDay = Now.getDay();
var startingTime = new Date(Now.getFullYear(), Now.getMonth(),  Now.getDate(), startingHour[CurrentDay], startingMin[CurrentDay]);
var closingTime = new Date(Now.getFullYear(), Now.getMonth(), Now.getDate(), closingHour[CurrentDay], closingMin[CurrentDay]);
var Open = (Now.getTime() > startingTime.getTime() && Now.getTime() < closingTime.getTime());
if (Open) {
    $('.openstatus').toggle();
}

将商店营业的小时和分钟定义为 var，并通过配置检查当前时间。

如果开放/关闭时间可能发生变化，似乎更容易更新。