php - PHP警告: Illegal string offset & Invalid argument supplied for foreach() [duplicate]

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Invalid argument supplied for foreach()

(19个回答)


6年前关闭。




没有任何结果时会出现以下两个错误:

中的字符串偏移量'artist'

为foreach()提供的无效参数

以下代码与用户搜索的结果相匹配，并通过last.fm API返回信息，该代码位于另一个文件中，不会引起问题。

当没有搜索结果并且foreach循环尝试不包含任何数据时，就会出现问题。需要的是某种错误捕获，而我尝试过的任何方法都没有起作用。

尝试将其作为foreach循环，catch语句似乎不起作用。

if(!isset($json['results']['artistmatches']['artist'][0]))
    {  
    echo '<div class="alert  alert-danger">Artists Not Found</div>';
    }
    else 
    { 
        foreach ($json['results']['artistmatches']['artist'] as $track) 
        {
            $artist = $track['name'];
            $image = $track['image'][3]['#text'];
            $url =  preg_replace("/ /s","_" , $artist); 
            if($artist&&$image)
            {
                include('./artist_short.php');      
            }
        }

    }

最佳答案

添加一条if语句，检查结果是否为数组。

if(is_array($json['results']['artistmatches'])) {

    foreach ($json['results']['artistmatches']['artist'] as $track) 
    {
        $artist = $track['name'];
        $image = $track['image'][3]['#text'];
        $url =  preg_replace("/ /s","_" , $artist); 

        if($artist&&$image)
        {
            include('./artist_short.php');      
        }
    }
} else {
 //handle case where the condition doesn't match.
}

关于php - PHP警告: Illegal string offset & Invalid argument supplied for foreach() [duplicate]，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/23372684/

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Answer 1

添加一条if语句，检查结果是否为数组。

if(is_array($json['results']['artistmatches'])) {

    foreach ($json['results']['artistmatches']['artist'] as $track) 
    {
        $artist = $track['name'];
        $image = $track['image'][3]['#text'];
        $url =  preg_replace("/ /s","_" , $artist); 

        if($artist&&$image)
        {
            include('./artist_short.php');      
        }
    }
} else {
 //handle case where the condition doesn't match.
}