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javascript - 从 ElasticSearch 获取 json 的子集

转载 作者:行者123 更新时间:2023-12-03 09:10:14 25 4
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我想要从 ElasticSearch 服务器获取 json 响应的子集。我是 ElasticSearch 和 JavaScript 的新手。请看一看。 json 文件是示例文件 here来自 ElasticSearch 文档。这是一个示例:

{
"took" : 1,
"timed_out" : false,
"_shards" : {
"total" : 5,
"successful" : 5,
"failed" : 0
},
"hits" : {
"total" : 1000,
"max_score" : 1.0,
"hits" : [ {
"_index" : "bank",
"_type" : "account",
"_id" : "4",
"_score" : 1.0,
"_source":{"account_number":4,"balance":27658,"firstname":"Rodriquez","lastname":"Flores","age":31,"gender":"F","address":"986 Wyckoff Avenue","employer":"Tourmania","email":"rodriquezflores@tourmania.com","city":"Eastvale","state":"HI"}
}, {
"_index" : "bank",
"_type" : "account",
"_id" : "9",
"_score" : 1.0,
"_source":{"account_number":9,"balance":24776,"firstname":"Opal","lastname":"Meadows","age":39,"gender":"M","address":"963 Neptune Avenue","employer":"Cedward","email":"opalmeadows@cedward.com","city":"Olney","state":"OH"}
}
................................
]
}
}

如何提取 account_number、余额和姓氏的数组,例如 [{"account_number":9,"balance":24776,"lastname":"Meadows"},{"account_number":4,"余额":27658,"姓氏":"弗洛雷斯"},……].

这是我使用的代码:

var deferred = $q.defer();          
$http.get("http://localhost:9200/bank/_search?q=*").success(function(data){

var country=data.hits.hists.map( function (count) {
return {
account_number: count._source.account_number,
balance: count._source.balance,
lastname: count._source.lastname
};
});

deferred.resolve(country);
});

return deferred.promise;

我从类似的代码中获得了灵感one用于 REST 调用。看来我得到的数据未定义。 ES 端需要配置吗?

最佳答案

您可以使用 source filtering 指示 ES 仅返回这些字段:

$http.get("http://localhost:9200/bank/_search?_source=account_number,balance,lastname&q=*").success(function(data){          

这样您就不必自己过滤字段。

那么下一行有一个拼写错误:hists 应该读取 hits

var country=data.hits.hits.map( function (count) {

请尝试一下。

关于javascript - 从 ElasticSearch 获取 json 的子集,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32098089/

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