python - 打开文件时lxml中的密码错误

Question

我的代码很简单；

f = open(r"C:\filepath\file.xml")
xml = f.read()
tree = etree.parse(xml)

运行此命令时，我得到了堆栈跟踪

tree = etree.parse(xml)
  File "src/lxml/lxml.etree.pyx", line 3427, in lxml.etree.parse (src\lxml\lxml.etree.c:79801)
  File "src/lxml/parser.pxi", line 1782, in lxml.etree._parseDocument (src\lxml\lxml.etree.c:115995)
  File "src/lxml/parser.pxi", line 1808, in lxml.etree._parseDocumentFromURL (src\lxml\lxml.etree.c:116345)
  File "src/lxml/parser.pxi", line 1712, in lxml.etree._parseDocFromFile (src\lxml\lxml.etree.c:115233)
  File "src/lxml/parser.pxi", line 1115, in lxml.etree._BaseParser._parseDocFromFile (src\lxml\lxml.etree.c:109930)
  File "src/lxml/parser.pxi", line 573, in lxml.etree._ParserContext._handleParseResultDoc (src\lxml\lxml.etree.c:103404)
  File "src/lxml/parser.pxi", line 683, in lxml.etree._handleParseResult (src\lxml\lxml.etree.c:105058)
  File "src/lxml/parser.pxi", line 611, in lxml.etree._raiseParseError (src\lxml\lxml.etree.c:103924)
IOError

这里发生了什么？

Answer 1

parse()接受XML文件的路径:

tree = etree.parse(r"C:\filepath\file.xml")

当前，您的代码将XML的实际内容传递给 parse()，这将触发该 IOError。您可以改用 fromstring()从包含实际XML数据的字符串中创建 Element对象。然后，如果需要，您可以根据先前创建的 ElementTree创建一个 Element对象:

f = open(r"C:\filepath\file.xml")
xml = f.read()
root = etree.fromstring(xml)
tree = etree.ElementTree(root)