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reactjs - 上传成功后如何获取Web API返回的响应?

转载 作者:行者123 更新时间:2023-12-03 08:55:35 25 4
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我已经检查了文档,但没有在任何地方可以找到我需要的要求的任何详细信息。

这是一个在上传时调用的 Web API 资源,该资源返回其文件名和内容的 json。

    [HttpPost, DisableRequestSizeLimit]
public ActionResult Upload()
{
try
{
var stamp = FileHelper.FormatShortDateForfilename(DateTime.Now, true);
var file = Request.Form.Files[0];
if (file.Length == 0)
throw new Exception("No file uploaded.");

var fileName = ContentDispositionHeaderValue.Parse(file.ContentDisposition).FileName.Trim('"');
fileName = $"[{stamp}] {fileName}";
var fullPath = Path.Combine(webRootPath, fileName);

var ext = Path.GetExtension(fileName);
if (!acceptables.Contains(ext.Replace(".", "")))
throw new Exception($"Only {String.Join("-", acceptables).ToUpper()} files are acceptables.");

using (var stream = new FileStream(fullPath, FileMode.Create))
{
file.CopyTo(stream);
}

dynamic upldData = new JObject();
upldData.filename = fileName;
upldData.Content = "........";
return Json(upldData.ToString());
}
catch (Exception ex)
{
//return Json("Upload Failed: " + ex.Message);
throw;
}
}

这是我的 ReactJS 脚本,我需要在其中访问该响应。

<FilePond ref={ref => this.pond = ref}
server="api/imports"
labelIdle={'Drag & Drop your CSV file here or <span class="filepond--label-action">Browse</span>'}
checkValidity={true}
acceptedFileTypes={['application/vnd.ms-excel']}
onupdatefiles={fs => {
this.setState({ hasFile: fs.length });
}}
onremovefile={(fs) => {
this.setState({ hasFile: fs && fs.length });
}}
onaddfile={fs => { this.setState({ hasFile: false }) }}
onprocessfile={(err, file) => {
console.log('FilePond ready for use', err, file);
console.log('test', file.serverId);
}}
/>

最佳答案

我只是花了一些时间来弄清楚这里发生了什么。这是在 filePond 内创建请求的主要功能。

const createProcessorFunction = (apiUrl = '', action, name) => {
// custom handler (should also handle file, load, error, progress and abort)
if (typeof action === 'function') {
return (...params) => action(name, ...params);
}

// no action supplied
if (!action || !isString(action.url)) {
return null;
}

// internal handler
return (file, metadata, load, error, progress, abort) => {
// set onload hanlder
const ondata = action.ondata || (fd => fd);
const onload = action.onload || (res => res);
const onerror = action.onerror || (res => null);

// no file received
if (!file) return;

// create formdata object
var formData = new FormData();

// add metadata under same name
if (isObject(metadata)) {
formData.append(name, JSON.stringify(metadata));
}

// Turn into an array of objects so no matter what the input, we can handle it the same way
(file instanceof Blob ? [{ name: null, file }] : file).forEach(item => {
formData.append(
name,
item.file,
item.name === null ? item.file.name : `${item.name}${item.file.name}`
);
});

// send request object
const request = sendRequest(ondata(formData), apiUrl + action.url, action);
request.onload = xhr => {
load(
createResponse(
'load',
xhr.status,
onload(xhr.response),
xhr.getAllResponseHeaders()
)
);
};

request.onerror = xhr => {
error(
createResponse(
'error',
xhr.status,
onerror(xhr.response) || xhr.statusText,
xhr.getAllResponseHeaders()
)
);
};

request.ontimeout = createTimeoutResponse(error);
request.onprogress = progress;
request.onabort = abort;

// should return request
return request;
};
};

如您所见,您可以将函数或对象作为 server 属性的值传递。您可以检查一些方法,例如 onloadonerrorondata 并尝试找到问题的解决方案。或者只是传递自定义函数并在其中执行您的请求,例如

<FilePond server={(...args) => this.handleUploadRequest(...args)} />

希望对你有帮助。谢谢

关于reactjs - 上传成功后如何获取Web API返回的响应?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55630508/

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