python - Python3 Try/Except block

Question

有人可以帮我了解以下问题吗？

我在简单的数字猜谜游戏中执行try/except块时遇到问题。如果删除初始输入的整数部分，则包含错误处理的函数可以正常工作。但是，如果这样做，游戏的其余部分将无法正常工作，因为据我了解，Python3接受输入并将其存储为字符串。那么如何获取我的异常(exception)来执行？任何帮助深表感谢。

谢谢，

# number game
import random




print ("Welcome to the guessing number game!\n\n")

winning_number= random.randrange(1, 11)
guess = int(input("Can you guess the lucky number.\nHint it's between 1 and 10!\n"))


def is_number(guess):
    try:
        int(guess)
    except ValueError:
        print ('You need to type a number\n')
        guess = int((input("Please input a number\n")))
        game(guess)



def compare(guess):
    if guess > winning_number:
        print ("Wrong, you're guess is too high.\n")
        guess = int(input("Guess againn\n"))
        game(guess)
    else:
        print ("Wrong, you're guess is too low.\n")
        guess = int(input("Guess again\n"))
        game(guess)



def game(guess):
    is_number(guess)
    if guess == winning_number:
        print ("You win!, You guessed the number!")
    else:
        compare(guess)

game(guess)

这是我输入除整数以外的任何内容时得到的...

欢迎来到猜数字游戏!

你能猜出幸运数字吗？
提示它在1到10之间!
F
追溯(最近一次通话):
在第10行中输入文件“C:/Users/mickyj209/PycharmProjects/Practice/NumberGuess.py”
guess = int(input(“您能猜出幸运数字吗？\ n提示它在1到10之间!\ n”)
ValueError:int()以10为底的无效文字:“f”

流程以退出代码1完成

Answer 1

您忘记了保存该时间的值(guess = int(guess))，没有在其中存储return的任何内容，只是让程序运行该函数，但没有根据结果做出决定。您还可以在异常处理中添加一个int(input(...，它本身可能会生成一个不会被捕获的异常。最初的猜测也不在try块中。

您可以重构该程序:

def game():

    print ("Welcome to the guessing number game!\n\n")

    winning_number = random.randrange(1, 11)
    print("Can you guess the lucky number?\nHint: it's between 1 and 10!\n")
    while 1:
        try:
            guess = int(input("Please input a number\n"))
        except ValueError:
            continue
        if guess > winning_number:
            print('Wrong - your guess is too high.')
        elif guess < winning_number:
            print('Wrong - your guess is too low.')
        else:
            print('You win! You guessed the number!')
            break