python - Python Twitter Tools-处理Twitter 404和401 API错误

Question

查询Twitter API时出现404和401错误，由于无法处理异常，我拉 friend 的脚本中断了。
研究并尝试添加以下try/except条款，但未记录异常，并且for循环停止。

first = 0
last = 15
while last < len(list)+16: #while last group of 15 items is lower than number of items in list#
    for item in list[first:last]: #parses twitter IDs in the list by groups of 15#
        try:
            results = twitter.friends.ids(skip_status="true",include_user_entities="false",count ="5000",user_id=item) #API query#
            results = str(results)
            text_file = open("output.txt", "a") #creates empty or opens current txt output / change path to desired output#
            text_file.write(str(item) + "," + results + "\n") #adds twitter ID, resulting friends list, and a line skip to the txt output#
            text_file.close()
            break
        except ValueError:
            text_file = open("output.txt", "a") #creates empty or opens current txt output / change path to desired output#
            text_file.write(str(item) + "," + "ERROR" + "\n") #adds twitter ID, resulting friends list, and a line skip to the txt output#
            text_file.close()
    print "Succesfully processed users " + str(list[first:last]) #returns recently processed group of 15 users#
    first = first + 15 #updates list navigation to move on to next group of 15#
    last = last + 15
    time.sleep(1000) #suspends activities for 1000 seconds to respect rate limit#

还研究了基于http响应 header 构建if语句，但是我不明白如何插入Python Twitter Tools“response.headers.get('h')”来做到这一点。处理和记录这些异常并使脚本继续提取数据的最佳方法是什么？

Answer 1

删除break块末尾的try:，并在continue块末尾添加except:。即:

first = 0
last = 15
while last < len(list)+16: #while last group of 15 items is lower than number of items in list#
    for item in list[first:last]: #parses twitter IDs in the list by groups of 15#
        try:
            results = twitter.friends.ids(skip_status="true",include_user_entities="false",count ="5000",user_id=item) #API query#
            results = str(results)
            text_file = open("output.txt", "a") #creates empty or opens current txt output / change path to desired output#
            text_file.write(str(item) + "," + results + "\n") #adds twitter ID, resulting friends list, and a line skip to the txt output#
            text_file.close()
            # break is not needed here!
        except ValueError:
            text_file = open("output.txt", "a") #creates empty or opens current txt output / change path to desired output#
            text_file.write(str(item) + "," + "ERROR" + "\n") #adds twitter ID, resulting friends list, and a line skip to the txt output#
            text_file.close()
            continue # You have dealt with the exception so don't stop
    print "Succesfully processed users " + str(list[first:last]) #returns recently processed group of 15 users#
    first = first + 15 #updates list navigation to move on to next group of 15#
    last = last + 15
    time.sleep(1000) #suspends activities for 1000 seconds to respect rate limit#

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