jquery - 快速捕获中 Unresolved 已识别错误

Question

多亏了社区，我昨天才解决了在转为Swift 2时的错误处理问题。这些更正实际上产生了一个新错误，我不知道如何纠正。以下是当前代码，该代码显示了Feed中的一些图片帖子:

override func viewDidAppear(animated: Bool) {
super.viewDidAppear(animated)

ParseHelper.timelineRequestForCurrentUser {
  (result: [AnyObject]?, error: NSError?) -> Void in
  self.posts = result as? [Post] ?? []

  for post in self.posts {
    do
    {
      let data = try post.imageFile?.getData()
    }
    catch
    {
      print("Error: \(error)")
      //Handle the error instead of print probably
    }
    post.image = UIImage(data: data!, scale:1.0)  --> where I get the error message "Use of unresolved identified 'data'"

  }

  self.tableView.reloadData()
}

此外，我在前面的方法中引用的ParseHelper文件中出现一个新错误。

static func timelineRequestForCurrentUser(completionBlock: PFArrayResultBlock) {
let followingQuery = PFQuery(className: "Follow")
followingQuery.whereKey("fromUser", equalTo:PFUser.currentUser()!)

let postsFromFollowedUsers = Post.query()
postsFromFollowedUsers!.whereKey("user", matchesKey: "toUser", inQuery: followingQuery)

let postsFromThisUser = Post.query()
postsFromThisUser!.whereKey("user", equalTo: PFUser.currentUser()!)

let query = PFQuery.orQueryWithSubqueries([postsFromFollowedUsers!, postsFromThisUser!])
query.includeKey("user")
query.orderByDescending("createdAt")

// 3
query.findObjectsInBackgroundWithBlock(completionBlock) --> I get an error message too here "Cannot convert value of type 'PFArrayResultBlock' to expected argument type 'PFQueryArrayResultBlock?'"

Answer 1

对Swift不太熟悉，但是编译器的输出很有意义。首先，let data声明的范围限于do/catch的do块。为了使catch块使用数据，必须在do/catch范围内重新声明数据。

let data : NSData? // assuming type is NSData (my point here is about scope)
do {
    data = try post.imageFile?.getData()
} catch {
    print("Error: \(error)")
    //Handle the error instead of print probably
}
// now data is in scope here...
post.image = UIImage(data: data!, scale:1.0)

第二个问题似乎是在这里将完成块声明为 PFArrayResultBlock类型的函数参数:

static func timelineRequestForCurrentUser(completionBlock: PFArrayResultBlock)

...但是parse希望将 PFQueryArrayResultBlock类型的块传递给 findObjectsInBackground。两者之间的区别似乎是数组元素的预期类型略有不同(查询的 [PFObject]?与 [AnyObject]?)。