java - 异常处理和 IO

Question

因此，我创建了一个程序，该程序加载具有以下格式的文件:John 55 18.27 然后将这三个变量(一旦拆分)传递到一个新创建的文件中。

我收到 1) Jack Turner 44 19.22 & 2) Mike 55.0 23.44 的异常错误
第一个错误是因为姓氏，另一个是整数，如 55.0
如何修复我的代码以处理这些异常？

import java.util.*;
import java.io.File;
import java.util.Scanner;


public class methods {
    private String name;
    private int hours;
    private double timeSpent;
    private double averageGPA; 

    private Scanner x;
    private StringTokenizer stk;
    private String[] storage = new String[11];
    private Formatter file;

    public void openFile(){
        try{
            x = new Scanner(new File("students.dat"));
        }
        catch(Exception e){
            System.out.println("could not find file");
        }
    }

    public void readFile(){
        int count = 0;
        while(x.hasNext()){

            storage[count] = x.nextLine();
            count ++;
        }
    }

    public void closeFile(){
        x.close();
    }

    public void stringTokenizer(){
        int count = 0;
        createNewFile();
        while(count < storage.length){

        stk = new StringTokenizer(storage[count]);
        name = stk.nextToken();
        hours = Integer.parseInt(stk.nextToken());
        timeSpent = Double.parseDouble(stk.nextToken());
        addRecords();
        count++;

        }
        file.close();

    }

    public void createNewFile(){
        try{
           file = new Formatter("skeleton.txt"); 
        }
        catch(Exception e){
            System.out.println("There has been an error");
        }
    }

    public void addRecords(){
        file.format("%s %s %s\n", name, hours, timeSpent);
    }

}  

公共(public)类 Lab1_a {

public static void main(String[] args) {
    int creditHrs;     // number of semester hours earned
double qualityPts; // number of quality points earned
double gpa;        // grade point (quality point) average

String line, name = "", inputName = "students.dat";
String outputName = "warning.dat";

    //Get File
    methods obj1 = new methods();


  //Create an Array of Strings
  obj1.openFile();
  obj1.readFile();



  obj1.createNewFile();
  obj1.stringTokenizer();
  obj1.closeFile();
}

}

Answer 1

一、看完name , 如果下一个标记无法解析为 double , 附加到 name中间有空格。继续直到找到 double .

一旦你找到了第一个 double ，将其转换为 int并存储为 hours .

解析 timeSpent像之前一样。

这里有一些(未经测试的)代码可以帮助您入门:

name = stk.nextToken();
String next;
while (true) {
    try {
        next = stk.nextToken();
        hours = (int)Double.parseDouble(next);
        break;
    } catch (NumberFormatException e) {
        name = name + " " + next;
    }
}
timeSpent = Double.parseDouble(stk.nextToken());