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python - 第一次识别输入错误,第二次开始运行

转载 作者:行者123 更新时间:2023-12-03 08:50:53 25 4
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当我尝试选择错误的选择时,第一次出现错误。第二次开始运行“选择级别”块。例如,如果我输入选择“12”,程序将返回错误并让我再次选择,而这次我输入“13”,它将返回“选择级别”块。我需要花点时间或什么时间来验证选择?

import random
import sys

choice = None

while choice != "0":
print('''
--------------------
Welcome to Hangman
--------------------

Please select a menu option:

0 - Exit
1 - Enter a new text file to be read:
2 - Play Game

''')

choice= input("Enter you choice: ")

if choice == "0":
sys.exit("Exiting from Python")

elif choice =="1":
while True:
try:
fileInput = input("Enter a new text file name: ")
List = open(fileInput).readlines()
break
except:
print ("\n Failed to open the file")
sys.exit()

elif choice == "2":
List = open("words_for_hangman.txt").readlines()

elif choice == " ":
choice = print("\n That is not a valit option! Please try again!")
choice = input("Choice:")

else:
choice = print("\n That is not a valid option! Please try again!")
choice = input("Choice: ")

print('''

Now select your difficulty level:

0 - EASY
1 - INTERMEDIATE
2 - HARD

''')

level= input("Enter your choice: ")
if level == "0":
word = random.choice(List)
word = word.strip()
hidden_word = "*" * len(word)
lives = 10
guessed = []
elif level == "1":
word = random.choice(List)
word = word.strip()
hidden_word = "*" * len(word)
lives = 7
guessed = []
elif level == "2":
word = random.choice(List)
word = word.strip()
hidden_word = "*" * len(word)
lives = 5
guessed = []


while lives != 0 and hidden_word != word:
print("\n-------------------------------")
print("The word is")
print(hidden_word.replace("_"," _ "))
print("\nThere are", len(word), "letters in this word")
print("So far the letters you have guessed are: ")
print(' '.join(guessed))
print("\n You have", lives,"lives remaining")
guess = input("\n Guess a letter: \n")
guess = guess.upper()
if len(guess) > 1:
guess = input("\n You can only guess one letter at a time!\n Try again: ")
guess = guess.upper()
elif guess== " ":
guess = input("\n You need to input a letter, not a space!\n Come on let's try again: ")
guess = guess.upper()
while guess in guessed:
print("\n You have already guessed that letter!")
guess = input("\n Please take another guess: ")
guess = guess.upper()
guessed.append(guess)
if guess in word:
print('''-------------------------------
''')
print("Well done!", guess.upper(),"is in the word")
word_so_far = ""
for i in range (len(word)):
if guess == str(word[i]):
word_so_far += guess
else:
word_so_far += hidden_word[i]
hidden_word = word_so_far
else:
print('''-------------------------------
''')
print("Sorry, but", guess, "is not in the word")
lives -= 1

if lives == 0:
print("GAME OVER! You have no lives left")
else:
print("\n CONGRATULATIONS! You have guessed the word")
print("The word was", word)
print("\nThank you for playing Hangman")

最佳答案

是的,您是第二个输入,实际上并没有得到检查。您需要将其放置在while循环中,以便始终返回到相同的输入并再次执行所有检查:

goodChoice = false
while not goodChoice:
#print text message
choice = input("Enter you choice: ")
if choice == 1:
goodchoice = True

#game code

上面的内容(没有您的功能)将永远发生,直到输入一个为1的选项为止,然后它将进入代码的其余部分

关于python - 第一次识别输入错误,第二次开始运行,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41089029/

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