ajax - ajax发布不捕获错误，总是捕获成功

Question

我有一个ajax post方法可以将新记录添加到数据库中，该过程本身可以正常运行，并且我的服务器端代码会捕获错误(重复输入等)。当发生错误时，ajax方法不会“看到”它，始终会调用“成功”功能。这是我的ajax发布方法

$.ajax({
                            url: '@Url.Action("Add", "Organisation")',
                            data: $form.serialize(),
                            async: true,
                            type: 'POST',
                            error: function (returnval) {
                                $form.parents('.bootbox').modal('hide');
                                bootbox.alert('There was an error saving this organisation : ' + returnval['responseText']);
                            },
                            success: function (returnval) {
                                // Hide the dialog
                                $form.parents('.bootbox').modal('hide');
                                bootbox.alert('New Organisation successfully added');
                            }
                        })

还有我 Controller 上的 Action 方法

[HttpPost]
    [ValidateAntiForgeryToken]
    public JsonResult Add(OrganisationEditCreateViewModel data)
    {
        InsertOrganisationRequest request = new InsertOrganisationRequest();
        IEnumerable<ModelError> allErrors = ModelState.Values.SelectMany(v => v.Errors);
        if (ModelState.IsValid)
        {
            var model = mapper.Map<OrganisationEditCreateViewModel, OrganisationDto>(data);
            request.organisation = model;
            var response = this._organisationService.InsertOrganisation(request);
            if (response.isSuccess)
            {
                return Json(new { success = true, responseText = "New organisation added successfully" }, JsonRequestBehavior.AllowGet);
            }
            else
            {
                return Json(new { success = false, responseText = "Error adding new organisation : " + response.Message }, JsonRequestBehavior.AllowGet);
            }
        }
        return Json(new { success = false, responseText = "Error adding new organisation : Invalid input" }, JsonRequestBehavior.AllowGet);
    }

因此，当我插入重复的记录时，服务器端代码会捕获该记录，并将此代码分支返回给我的ajax调用

return Json(new {success = false，responseText =“添加新组织时出错:” + response.Message}，JsonRequestBehavior.AllowGet);

但是ajax调用总是调用这段代码

success: function (returnval) {
                                // Hide the dialog
                                $form.parents('.bootbox').modal('hide');
                                bootbox.alert('New Organisation successfully added');
                            }

错误部分永远不会被调用，我在做什么错？

Answer 1

更新您的成功方法!

 success: function (returnval) 
        {
           if(returnval.success=true)
           {
             // Hide the dialog
             $form.parents('.bootbox').modal('hide');
            bootbox.alert('New Organisation successfully added');
           }
           if(returnval.success=false)
           {
             $form.parents('.bootbox').modal('hide');
             bootbox.alert('There was an error saving this organisation : ' + returnval['responseText']);
           }
        }

希望有帮助!