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python - Instagram python bot,当我运行错误时如何关闭并重新启动?

转载 作者:行者123 更新时间:2023-12-03 08:48:47 26 4
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所以我在GitHub上找到了这个Bot for Instagram。
我已经编辑了脚本,因此我猜想它会运行最长的时间,直到我连续遇到3个“错误400”,然后脚本停止以防止被禁止。

我想做一个循环,当我遇到错误时,它会关闭并重新启动。

#!/usr/bin/env python
# -*- coding: utf-8 -*-
import os
import sys
import time

sys.path.append(os.path.join(sys.path[0], 'src'))

from check_status import check_status
from feed_scanner import feed_scanner
from follow_protocol import follow_protocol
from instabot import InstaBot
from unfollow_protocol import unfollow_protocol

bot = InstaBot(
login="USERNAME",
password="PASSWORD",
like_per_day=2500,
comments_per_day=1500,
tag_list=['photo', '', 'car', 'nature', 'city'],
tag_blacklist=['racist', 'example', 'example', 'example', ],
user_blacklist={},
max_like_for_one_tag=50,
follow_per_day=0,
follow_time=1 * 60,
unfollow_per_day=300,
unfollow_break_min=15,
unfollow_break_max=30,
log_mod=0,
proxy='',
# List of list of words, each of which will be used to generate comment
# For example: "This shot feels wow!"
comment_list=[["this", "the", "your"],
["photo", "picture", "pic", "shot", "snapshot"],
["is", "looks", "is really"],
["great", "super", "good", "very good", "good", "wow",
"WOW", "cool", "GREAT","magnificent", "magical",
"very cool", "stylish", "beautiful", "so beautiful",
"so stylish", "so professional", "lovely",
"so lovely", "glorious","so glorious",
"very glorious", "adorable", "excellent", "amazing"],
[".", "..", "...", "!", "!!", "!!!"]],
# Use unwanted_username_list to block usernames containing a string
## Will do partial matches; i.e. 'mozart' will block 'legend_mozart'
### 'free_followers' will be blocked because it contains 'free'
unwanted_username_list=[
'second', 'stuff', 'art', 'project', 'love', 'life', 'food', 'blog',
'free', 'keren', 'photo', 'graphy', 'indo', 'travel', 'art', 'shop',
'store', 'sex', 'toko', 'jual', 'online', 'murah', 'jam', 'kaos',
'case', 'baju', 'fashion', 'corp', 'tas', 'butik', 'grosir', 'karpet',
'sosis', 'salon', 'skin', 'care', 'cloth', 'tech', 'rental', 'kamera',
'beauty', 'express', 'kredit', 'collection', 'impor', 'preloved',
'follow', 'follower', 'gain', '.id', '_id', 'bags'
],
unfollow_whitelist=['example_user_1', 'example_user_2'])
while True:

#print("# MODE 0 = ORIGINAL MODE BY LEVPASHA")
#print("## MODE 1 = MODIFIED MODE BY KEMONG")
#print("### MODE 2 = ORIGINAL MODE + UNFOLLOW WHO DON'T FOLLOW BACK")
#print("#### MODE 3 = MODIFIED MODE : UNFOLLOW USERS WHO DON'T FOLLOW YOU BASED ON RECENT FEED")
#print("##### MODE 4 = MODIFIED MODE : FOLLOW USERS BASED ON RECENT FEED ONLY")
#print("###### MODE 5 = MODIFIED MODE : JUST UNFOLLOW EVERYBODY, EITHER YOUR FOLLOWER OR NOT")

################################
## WARNING ###
################################

# DON'T USE MODE 5 FOR A LONG PERIOD. YOU RISK YOUR ACCOUNT FROM GETTING BANNED
## USE MODE 5 IN BURST MODE, USE IT TO UNFOLLOW PEOPLE AS MANY AS YOU WANT IN SHORT TIME PERIOD

mode = 0

#print("You choose mode : %i" %(mode))
#print("CTRL + C to cancel this operation or wait 30 seconds to start")
#time.sleep(30)

if mode == 0:
bot.new_auto_mod()

elif mode == 1:
check_status(bot)
while bot.self_following - bot.self_follower > 200:
unfollow_protocol(bot)
time.sleep(10 * 60)
check_status(bot)
while bot.self_following - bot.self_follower < 400:
while len(bot.user_info_list) < 50:
feed_scanner(bot)
time.sleep(5 * 60)
follow_protocol(bot)
time.sleep(10 * 60)
check_status(bot)

elif mode == 2:
bot.bot_mode = 1
bot.new_auto_mod()

elif mode == 3:
unfollow_protocol(bot)
time.sleep(10 * 60)

elif mode == 4:
feed_scanner(bot)
time.sleep(60)
follow_protocol(bot)
time.sleep(10 * 60)

elif mode == 5:
bot.bot_mode = 2
unfollow_protocol(bot)

else:
print("Wrong mode!")
  • 注意:
    编辑了一些描述,以使其对他/她问的内容更具可读性和特定性
    *
  • 最佳答案

    我意识到我遇到了很多错误,因为我的计算机上没有pyLint要求

    关于python - Instagram python bot,当我运行错误时如何关闭并重新启动?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/47069054/

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