python - Odoo 10 : Catch the UserError and show it to webpage

Question

我有一个 Controller ，它在models.py中调用 action_approve 函数，最后返回一个网页:

class Holiday(http.Controller):
    @http.route('/Approve', auth='public',type='http', methods=['GET'], website=True)
    def index(self,resid):

        record = http.request.env['hr.holidays'].search([('id', '=', resid)])
        print str(record)
        result=record.action_approve()
        return http.request.render('holiday.approve_page')

这是 action_approve 函数，具有 UserError 语句:

@api.multi
    def action_approve(self):
        # if double_validation: this method is the first approval approval
        # if not double_validation: this method calls action_validate() below
        print "holiday calleds"
        if not self.env.user.has_group('hr_holidays.group_hr_holidays_manager'):
            raise UserError(_('Only Leads can approve leave requests.'))
            return False
        manager = self.env['hr.employee'].search([('user_id', '=', self.env.uid)], limit=1)

        notification=Notification()
        notification.notifyEmployee(self,'Approved')

        for holiday in self:
            if holiday.state != 'confirm':
                raise UserError(_('Leave request must be confirmed ("To Approve") in order to approve it.'))
                return False
            if holiday.double_validation:
                return holiday.write({'state': 'validate1', 'manager_id': manager.id if manager else False})
            else:
                holiday.action_validate()

我想捕获此 UserError 消息，并将其在网页上显示给用户。我怎样才能做到这一点？

Answer 1

此代码有效:

try:
            record.action_approve()

except UserError,e:
            return http.request.render('holiday.approve_page', {'errorMsg': e[0]})