c# - 如何在引发异常之前将错误消息传递回

Question

我有以下代码收到错误消息。我想在引发异常之前将其传递给字符串，这是我的代码

ValidateError(authDeserialized, "Succeed", "error", "failed"); //the validateError is a function as indicated below
Model.Response= authResponse.Content;

 protected static void ValidateError(dynamic response, string validStatus,string categoryMatch, string message)
        {  
            if (response.result.status != validStatus)
            {
                try
                {
                    var category = response.result.category;
                    if (category == categoryMatch)
                          message=ErrorCodes.MessageFor(code,description);
      //so i get the message back fine here but now how do i pass it back to this line   Model.Response= authResponse.Content; so that it can get saved?
                }
                catch (Exception) { }
                throw new Exception(message ?? "Request was not successfull");
            }
        }

Answer 1

由于您已经将message发送到ValidateError()方法，因此将该参数作为 out parameter传递，如果您为其分配了新值，它将更新message的值，然后它将更新消息并且外部环境可以访问。

string failureMessage = "failed";
ValidateError(authDeserialized, "Succeed", "error", out failureMessage);
                                                  //^^^ This is what you have to change
//Now you can assign failureMessage to any other value
Model.Response= authResponse.Content;

protected static void ValidateError(dynamic response, string validStatus,string categoryMatch, out string message)
{                                                                                            //^^^ This is what you have to change
      if (response.result.status != validStatus)
      {
          try
          {
               var category = response.result.category;
               if (category == categoryMatch)
                   message=ErrorCodes.MessageFor(code,description);    //so i get the message back fine here but now how do i pass it back to this line   Model.Response= authResponse.Content; so that it can get saved?
          }
          catch (Exception) { }
          throw new Exception(message ?? "Request was not successfull");
      }
}

这样，您可以在引发错误之前为失败消息分配值。

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