amazon-web-services - 在 terraform 中，如何输出 aws_route53_record 别名值？

Question

Terraform v0.12.x

我正在创建一个 AWS Route53 记录，如下所示，它的创建没有任何问题。

data "aws_route53_zone" "zone" {
  name         = "my.domain.com."
  private_zone = true
}

resource "aws_route53_record" "record" {
  zone_id = data.aws_route53_zone.zone.zone_id
  name    = "${var.record_name}.${data.aws_route53_zone.zone.name}"
  type    = "A"
  alias {
    name                   = var.alias_record
    zone_id                = var.alias_zone_id
    evaluate_target_health = false
  }
}

现在我想输出别名的值，我尝试了

output "alias_name" {
  value = aws_route53_record.record.alias.name
}

或

output "alias_name" {
  value = aws_route53_record.record.alias["name"]
}

但出现错误

Block type "alias" is represented by a set of objects, and set elements do not
have addressable keys. To find elements matching specific criteria, use a
"for" expression with an "if" clause.

正确的语法是什么？

Answer 1

别名是一组对象和集合 are :

a collection of unique values that do not have any secondary identifiers or ordering.

所以你无法对它们建立索引。因此，在您的情况下，要输出可以使用的别名值:

output "alias_name" {
  value = aws_route53_record.record.alias.*.name
}

# or

output "alias_name2" {
  value = aws_route53_record.record.alias[*].name
}