php - 获取执行 “No Matter What”的特定代码行

Question

下面是在执行时引发一些错误的代码。我想做的是无论什么(错误或无错误)都将执行代码的最后一行。

<?php
require 'main.php';
function create_photo($file_path) {
  # Upload the received image file to Cloudinary 
  @$result = \Cloudinary\Uploader::upload($file_path, array(
    "tags" => "backend_photo_album",
  ));
  @unlink($file_path);
  error_log("Upload result: " . \PhotoAlbum\ret_var_dump($result));
  $photo = \PhotoAlbum\create_photo_model($result);
  return $result;
}
$files = $_FILES["files"];
$files = is_array($files) ? $files : array($files);
$files_data = array();
foreach ($files["tmp_name"] as $index => $value) {
  array_push($files_data, create_photo($value));
}
?>
<script>window.location.replace('index.html')</script>

任何帮助将非常感激。谢谢

Answer 1

我认为根据您的php版本，您可以使用“try/catch/finally”块，例如:

try
{
     // code that may throw an exception
}
catch(Exeption $e) // The exception you want to catch
{
     // Exception treatment
}
finally
{
     // Executed no matter what
}

也许看看如何使用它。