python - 在python3中发生错误时询问输入内容

Question

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Asking the user for input until they give a valid response

(21个回答)


6年前关闭。




在这段代码中，我正在寻找输入:

mode = input("Generate S1(0) or S2(1)?\n")
if mode == "0":
    mode = "S1"
elif mode == "1":
    mode = "S2"
else:
    print("Mode not recogised!")

为了能够更好地处理错误(模式> 1)，即当遇到else条件时，我希望代码再次询问输入。

任何想法我该怎么做或我正在寻找什么功能？

最佳答案

mode = None
while not mode:
    answer = input("Generate S1(0) or S2(1)?\n")
    if answer == "0":
        mode = "S1"
    elif answer == "1":
        mode = "S2"
    else:
        print("Mode not recogised!")

关于python - 在python3中发生错误时询问输入内容，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/23343246/

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Answer 1

mode = None
while not mode:
    answer = input("Generate S1(0) or S2(1)?\n")
    if answer == "0":
        mode = "S1"
    elif answer == "1":
        mode = "S2"
    else:
        print("Mode not recogised!")