python - 按下按钮pyqt5后无法打开新窗口

Question

我学习pyqt5并尝试通过单击另一个窗口中的按钮来打开一个新窗口。如果没有input()函数，它将立即关闭打开的窗口，因此我将input()保持打开状态。该窗口将打开很长时间，但随后已停止工作。有人能帮我吗 ？谢谢

import sys
from PyQt5.QtWidgets import QApplication, QPushButton,QMainWindow,QWidget
from PyQt5.QtGui import QIcon
from PyQt5.QtCore import pyqtSlot


class App1(QWidget):

    def __init__(self):
        super().__init__()
        self.title = 'open window'
        self.left = 60
        self.top = 60
        self.width = 320
        self.height = 200
        self.initUI()

    def initUI(self):
        self.setWindowTitle(self.title)
        self.setGeometry(self.left, self.top, self.width, self.height)

        self.show()
        m.getch()
        input()                  '''here is the problem'''

class App(QMainWindow):

    def __init__(self):
        super().__init__()
        self.title = 'PyQt5 button - pythonspot.com'
        self.left = 200
        self.top = 200
        self.width = 320
        self.height = 200
        self.initUI()

    def initUI(self):
        self.setWindowTitle(self.title)
        self.setGeometry(self.left, self.top, self.width, self.height)

        button = QPushButton('PyQt5 button', self)
        button.setToolTip('This is an example button')
        button.move(100, 70)
        button.clicked.connect(self.on_click)

        self.show()

    @pyqtSlot()
    def on_click(self):

        app1 = QApplication(sys.argv)
        ex1 = App1()
        sys.exit(app1.exec_())



if __name__ == '__main__':
    app = QApplication(sys.argv)
    ex = App()
    sys.exit(app.exec_())

Answer 1

您需要保存对窗口的引用，否则在on_click()完成执行时将对其进行垃圾收集。最简单的方法是通过使用App将其存储在self中

@pyqtSlot()
def on_click(self):
    self.ex1 = App1()