c# - 返回Task 方法的JSON错误消息

Question

我创建了一个ASP.NET Web API，它将调用Java Web服务并以JSON显示一些结果。当Java Web服务未运行时，我收到以下错误消息:

{"Message":"An error has occurred.","ExceptionMessage":"The method or operation is not implemented.","ExceptionType":"System.NotImplementedException","StackTrace":" at ApiClientJavaWebService.Models.RestfulClient.InternalServerError(Exception exception) in C:\Users\attsuap1\Desktop\Server Project\ApiClientJavaWebService\ApiClientJavaWebService\Models\RestfulClient.cs:line 43\r\n at ApiClientJavaWebService.Models.RestfulClient.d__3.MoveNext() in C:\Users\attsuap1\Desktop\Server Project\ApiClientJavaWebService\ApiClientJavaWebService\Models\RestfulClient.cs:line 36\r\n--- End of stack trace from previous location where exception was thrown ---\r\n at System.Runtime.CompilerServices.TaskAwaiter.ThrowForNonSuccess(Task task)\r\n at System.Runtime.CompilerServices.TaskAwaiter.HandleNonSuccessAndDebuggerNotification(Task task)\r\n at System.Runtime.CompilerServices.TaskAwaiter 1.GetResult()\r\n at ApiClientJavaWebService.Controllers.AdditionController.d__1.MoveNext() in C:\Users\attsuap1\Desktop\Server Project\ApiClientJavaWebService\ApiClientJavaWebService\Controllers\AdditionController.cs:line 20\r\n--- End of stack trace from previous location where exception was thrown ---\r\n at System.Runtime.CompilerServices.TaskAwaiter.ThrowForNonSuccess(Task task)\r\n at System.Runtime.CompilerServices.TaskAwaiter.HandleNonSuccessAndDebuggerNotification(Task task)\r\n at System.Threading.Tasks.TaskHelpersExtensions.d__3`1.MoveNext()\r\n--- End of stack trace from previous location where exception was thrown ---\r\n at System.Runtime.CompilerServices.TaskAwaiter.ThrowForNonSuccess(Task task)\r\n at System.Runtime.CompilerServices.TaskAwaiter.HandleNonSuccessAndDebuggerNotification(Task task)\r\n at System.Web.Http.Controllers.ApiControllerActionInvoker.d__0.MoveNext()\r\n--- End of stack trace from previous location where exception was thrown ---\r\n at System.Runtime.CompilerServices.TaskAwaiter.ThrowForNonSuccess(Task task)\r\n at System.Runtime.CompilerServices.TaskAwaiter.HandleNonSuccessAndDebuggerNotification(Task task)\r\n at System.Web.Http.Controllers.ActionFilterResult.d__2.MoveNext()\r\n--- End of stack trace from previous location where exception was thrown ---\r\n at System.Runtime.CompilerServices.TaskAwaiter.ThrowForNonSuccess(Task task)\r\n at System.Runtime.CompilerServices.TaskAwaiter.HandleNonSuccessAndDebuggerNotification(Task task)\r\n at System.Web.Http.Dispatcher.HttpControllerDispatcher.d__1.MoveNext()"}

我该如何更改以使错误消息显示为 {"The server is not running."}？

这是我的代码:

AdditionClient.cs

public class RestfulClient
{
    private static HttpClient client;
    private static string BASE_URL = "http://localhost:8080/";

    static RestfulClient()
    {
        client = new HttpClient();
        client.BaseAddress = new Uri(BASE_URL);
        client.DefaultRequestHeaders.Accept.Add(
            new MediaTypeWithQualityHeaderValue("application/json"));
    }

    public async Task<string> addition(int firstNumber, int secondNumber)
    {

        try
        {
            var endpoint = string.Format("addition/{0}/{1}", firstNumber, secondNumber);
            var response = await client.GetAsync(endpoint);
            return await response.Content.ReadAsStringAsync();
        }

        catch (Exception e)
        {

        }

        return null;
    }
}

AdditionController.cs

public class AdditionController : ApiController
{
    private RestfulClient restfulClient = new RestfulClient();
    public async Task<IHttpActionResult> Get(int firstNumber, int secondNumber)
    {
        var result = await restfulClient.addition(firstNumber, secondNumber);
        var resultDTO = JsonConvert.DeserializeObject<Temp>(result);
        return Json(resultDTO);
    }
}

有人请帮我。提前非常感谢您。

Answer 1

我认为，您无法在要提取数据的服务器中管理抛出异常消息。所以，为什么不过滤异常呢？

        try
        {
            var endpoint = string.Format("addition/{0}/{1}", firstNumber, secondNumber);
            var response = await client.GetAsync(endpoint);
            return await response.Content.ReadAsStringAsync();
        }

        catch (Exception e)
        {
            if (e.InnerException.Message == "The method or operation is not implemented")
            {
                //Do something
            }
        }