python - 简单IF的语法错误。

Question

在您问之前，我确实查看了其他答案和问题，它们似乎都是相同的，是的，我确实添加了，但仍然没有。好的，所以我有一个带有菜单的程序，在菜单选择中，它总是在“:”冒号处出现语法错误，请帮助我尝试了一切。
这是代码:

def main():
    print("Hello and Welcome to the 'Say When' program")

    print("1:Class\n2:Priamry\n3:Secondary\n4:FirstGag\n5:SecondGag")
    menu = (input("What would you like to search?: ")
            if menu == '1':
                print("You chose Class")
                list = ['Assault', 'Engineer', 'Support', 'Recon']
                from random import choice
                print(choice(list))

            elif menu == '2'
                print("nice")

错误=语法错误，然后以红色突出显示“ :”。

Answer 1

您在input函数上缺少了一个圆括号，根本不需要。

menu = input("What would you like to search?: ")

完整的固定代码:

def main():
    print("Hello and Welcome to the 'Say When' program")

    print("1:Class\n2:Priamry\n3:Secondary\n4:FirstGag\n5:SecondGag")
    menu = input("What would you like to search?: ")
    if menu == '1':
        print("You chose Class")
        list = ['Assault', 'Engineer', 'Support', 'Recon']
        from random import choice
        print(choice(list))

    elif menu == '2':
        print("nice")