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syntax-error - verilog程序计数器语法错误

转载 作者:行者123 更新时间:2023-12-03 08:21:14 27 4
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所以我在程序计数器测试台上遇到语法错误,无法弄清楚为什么我不断得到
以下verilog源具有语法错误:
“pc_tb.v”,20: token 为“初始”
初始
^

我使用的是最初的错误吗?制作流水线数据路径,这是到目前为止我唯一无法使用的部分

//PC_TB.V USED TO TEST THE PC MODULE
`include"pc.v"
module pc_tb;
wire[15:0]out;
reg stall,hold
reg[9:0]Mux,Haz
reg[7:0]Mem[0:65535];
ProgramCounter g1(stall,hold,Mem,out,Mux,Haz);
initial begin
stall=1'b0
hold=1'b0;
Mem=0;
Mux=9'b000000010;
Haz=9'b000000000;
#5 Mem[2]=1;
#10 hold=1'b1;
#30 halt=1'b1;
#40
initial
#100 $finish;
end
endmodule

最佳答案

您无法在initial块内声明另一个initial块,因此您需要关闭begin(此处为更正后的代码,请参见注释以进行更正):

//PC_TB.V USED TO TEST THE PC MODULE
`include"pc.v"
`define MEM_SIZE 65535

module pc_tb;
wire [15:0] out;
reg stall, hold; // Missing ;
reg [9:0] Mux, Haz; // Missing ;
reg [7:0] Mem[0:`MEM_SIZE-1]; // Convert to macro
integer i;

ProgramCounter g1(stall, hold, Mem, out, Mux, Haz);

// First initial block
initial begin
stall = 1'b0; // Missing ;
hold = 1'b0;
// Canot set unpacked array to 0, need to loop through to set each element
for (i = 0; i < `MEM_SIZE; i = i + 1) begin
Mem[i] = 8'd0;
end
Mux = 9'b000000010;
Haz = 9'b000000000;

#5 Mem[2] = 1;
#10 hold = 1'b1;
#30 halt = 1'b1; // halt undeclared, not sure what you meant to do here
// #40 does nothing here
end // This end was missing

// Second initial block
initial begin
#100 $finish; // 100 time units from start, simulation will terminate
end
endmodule

关于syntax-error - verilog程序计数器语法错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36970163/

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