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python-3.x - 程序语法错误

转载 作者:行者123 更新时间:2023-12-03 08:21:11 26 4
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我已经开始研究该程序,该程序应该对您播放摇滚剪刀纸。我尝试了不同的模型,这是最接近的模型。唯一的问题是它有一个语法错误,我不知道如何解决。

  #Macchiat0
#3, 6, 2016

#3. RPS is played between the computer and a single user.
#The player is prompted for a throw when 1 corresponds
#to Rock, 2 to Paper, and 3 to Scissors.
#A random number between 1 and 3 is generated for the computer throw.
#The winner is determined based on the rules of Rock Paper and Scissors.

#Program Menu

import random
end_game = True
while end_game == True:
print('1. Enter 1 for Rock ')
print('2. Enter 2 for Paper ')
print('3. Enter 3 for Scissors ')
print('4. Quit')
ans = int(input('What do you want to do?: '))
if ans=="1":
print("\n Enter 1 for Rock: ")
if Player game = 1
print('You win')
if Player game = 2
print('You loose')
if Player game = 3
print('You draw')
if ans =="2":
print("\n Enter 2 for Paper: ")
if Player game = 1
print('You win')
if Player game = 2
print('You loose')
if Player game = 3
print('You draw')
if ans =="3":
print("\n Enter 3 for Scissors: ")
if Player game = 1
print('You win')
if Player game = 2
print('You loose')
if Player game = 3
print('You draw')
elif ans=="4":
print("\n Goodbye")
break
else:
print("\n Not Valid Choice Try Again")

最佳答案

  • 如果用2个空格表示,则所有第一行(包括第一个)都包括在内。删除它们。
  • 如果Player game = 1,则为
  • ;如果-子句应以结尾,则所有相似:
  • 什么是玩家游戏?符号玩家游戏= 1毫无意义。您是否应该将答案与某个随机值进行比较?也应该有==而不是=

  • 只是很少注意到。真正的答案是在运行脚本时检查输出。它将告诉您出了什么问题。

    您的问题对SO来说不是最好的,有人会因此而绞死我,但是...该死,这是星期五!干得好:
    import random
    end_game = False

    def intToRPS(i):
    if i == 1:
    return 'Rock'
    elif i == 2:
    return 'Paper'
    elif i == 3:
    return 'Scissors'

    return ''

    while end_game == False:
    print('1. Enter 1 for Rock ')
    print('2. Enter 2 for Paper ')
    print('3. Enter 3 for Scissors ')
    print('4. Quit')
    ans = int(input('What do you want to do?: '))
    comp = random.randint(1, 3)

    if ans > 0 and ans < 4:
    msg = 'You chose ' + intToRPS(ans) + ' and computer chose ' + intToRPS(comp)
    print(msg)

    if ans == comp:
    print('Draw')
    elif ans == 1 and comp == 2: #Rock vs Paper
    print('You loose')
    elif ans == 1 and comp == 3: #Rock vs Scissors
    print('You win')
    elif ans == 2 and comp == 1: #Paper vs Rock
    print('You win')
    elif ans == 2 and comp == 3: #Paper vs Scissors
    print('You loose')
    elif ans == 3 and comp == 1: #Scissors vs Rock
    print('You loose')
    elif ans == 3 and comp == 2: #Scissors vs Paper
    print('You win')
    elif ans=="4":
    print("\n Goodbye")
    end_game = True
    break
    else:
    print("\n Not Valid Choice Try Again")

    关于python-3.x - 程序语法错误,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37614436/

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