hibernate - hql 加入@CollectionTable

Question

我有一个域 Service带收藏tags如下:

@Entity
public class Service extends AbstractEntity<Long> {
            private static final long serialVersionUID = 9116959642944725990L;

        @ElementCollection(fetch = FetchType.EAGER, targetClass = java.lang.String.class)
        @CollectionTable(name = "service_tags", joinColumns = @JoinColumn(name = "s_id"))
        @Column(name = "tag")
        private Set<String> tags;
    }

我要选择 Service s with特别 KEY的 Service.tags .

hql加盟Service至 Service.tags如下:

select s from Service s INNER JOIN s.tags t where s.status=0 and (s.serviceType=9 or t.tag in ('College'))

但是，在 hql 之上返回我，但有以下异常:

Caused by: java.lang.IllegalArgumentException: org.hibernate.QueryException: cannot dereference scalar collection element: tag [select s from com.zazzercode.domain.Service s INNER JOIN s.tags t where s.status=0 and (s.serviceType=9 or t.tag in ('College')) ]

select s from Service s INNER JOIN s.tags t where s.status=0虽然有效。

看着 JPQL querying a collection of non-entites ，我试过如下

"select s from Service s where s.status=0 and s.priviligedUser.priviligedUserType IN (2,4) and (s.serviceType=9 or (KEY(s.tags)='tag' and (VALUE(s.tags)='College'))"

得到以下异常:

Caused by: org.hibernate.hql.ast.QuerySyntaxException: unexpected token: null near line 1, column 188 [select s from com.esewa.server.entity.Service s where s.status=0 and (s.serviceType=9 or (KEY(s.tags)='tag' and (VALUE(s.tags)='College'))]

我也取得了同样的成绩 using criteria api几个月前。

Answer 1

感谢 JPQL querying a collection of non-entites

以下代码有效!!!

"select s from Service s INNER JOIN s.tags t where s.status=0 and and (s.serviceType=9 or  VALUE(s.tags) in ('College')) "