python - 当用户输入0时，如何打印程序并继续而不是崩溃？

Question

我正在让用户输入骰子的边数。如果有人输入0，程序将崩溃。如果他们输入字母或浮点数，则会打印出来，请输入一个整数。用户输入0时如何打印程序？ IndexError:无法从空序列中选择。

class Dice():

    def __init__(self, numberOfSides):
        self.numberOfSides = numberOfSides


    def rollDice(self):

        Dice.diceSides = list(range(1, self.numberOfSides + 1))
        return random.choice(Dice.diceSides)

def startRolling():

    while True:

        try:
            userInput = int(input("Enter the number of sides your dice has: "))
        except (ValueError, IndexError):
            print("Please enter a whole number.")
            continue
        else:
            break

    diceRolled = Dice(numberOfSides=userInput).rollDice()
    print("You rolled a {}.".format(diceRolled))

到目前为止，我已经尝试过了，但没有成功:

try:
except (ValueError, IndexError):
    print("Please enter a number.")
    continue

Answer 1

检查try/except之后的数字。

def startRolling():

    while True:

        try:
            userInput = int(input("Enter the number of sides your dice has: "))

        except ValueError:
            print("Please enter a whole number: ")
            continue

        if userInput != 0:
            break
        else:
            print("Please enter a non-zero number")