python - 我如何在Python中使用if/elif创建一个while循环而又没有语法错误

Question

我正在尝试创建一个具有三个选项的应用程序。

如果用户选择1，则popchange将运行，
如果用户选择2，则住房将运行，我需要该应用程序继续运行，直到用户选择3并退出该应用程序。

我的代码在下面，但是它不断返回语法错误，我不知道为什么。

import pandas as pd
import numpy as np
import matplotlib.pyplot as plt

print("\nWelcome to the data analysis app")

choice = ''

while choice != '3':
   print("Select the file you want to analyze: ")
   print("[1]:Enter 1 for Population Data  ")
   print("[2]: Enter 2 for Houseing Data  ")
   print("[3]: Enter 3 to Exit the application")

choice = input("\n What is your choice?")

if choice == '1':
  popchange= pd.read_csv("PopChange.csv")
  popchange_selected = popchange[["Pop Apr 1","Pop Jul 1", "Change Pop"]] 
  print("You selected PopChange")
  print(popchange_selected.describe())

elif choice == '2':
  housing=pd.read_csv("Housing.csv")
  housing_selected = housing[["AGE", "BEDRMS", "BUILT", "ROOMS", "UTILITY","WEIGHT","NUNITS" ]] 
  print("You selected Houseing")
  print(housing_selected.describe()

elif choice == '3':
  print("You selected 3.")
  print("Thanks for trying the application")

else:
  print("Invalid input, try again")

谁能告诉我为什么这会给我错误

elif choice == '3':
   ^
SyntaxError: invalid syntax        

Answer 1

您在错误上方的行中缺少右括号。

print(housing_selected.describe())
                                 ^