作者热门文章
- html - 出于某种原因,IE8 对我的 Sass 文件中继承的 html5 CSS 不友好?
- JMeter 在响应断言中使用 span 标签的问题
- html - 在 :hover and :active? 上具有不同效果的 CSS 动画
- html - 相对于居中的 html 内容固定的 CSS 重复背景?
我收到以下错误消息,我已经调试了两个标识插入,并且它们执行都没有问题。以前有人遇到过此错误,有人知道如何解决此问题吗?
Msg 8101, Level 16, State 1, Line 1
An explicit value for the identity column in table 'c365online_script1.dbo.tProperty' can only be specified when a column list is used and IDENTITY_INSERT is ON.
declare @Source_Database_Name varchar(255) = 'Production2';
declare @Destination_Database_Name varchar(255) = 'c365online_script1';
declare @Company_Id int = 1 --declare a companyid
CREATE TABLE #CompanyID (ID bigint)
INSERT INTO #CompanyID(ID)
VALUES('15')
-- Copy over company records from tCompanytable
--FIRST CURSOR LOOP THROUGH THIS TABLE
CREATE TABLE #TableList (
processorder int,
tablename NVARCHAR(100)
)
INSERT INTO #TableList (processorder, tablename )
VALUES
(1, 'tProperty');
DECLARE @Counter INT = 0 -- counting variable
----------- Cursor specific code starts here ------------
-- company cursor
declare copyCompanyDataCursor CURSOR fast_forward FOR
SELECT ID from #CompanyID;
open copyCompanyDataCursor
fetch next from copyCompanyDataCursor into @Company_Id;
WHILE @@FETCH_STATUS = 0
BEGIN
declare @processorder int;
declare @tablename varchar(500);
-- table cursor
declare copyTableDataCursor CURSOR fast_forward FOR
SELECT processorder,tablename from #TableList order by processorder;
open copyTableDataCursor
fetch next from copyTableDataCursor into @processorder, @tablename;
while @@FETCH_STATUS = 0
BEGIN
SET IDENTITY_INSERT [c365online_script1].[dbo].[tCompany] ON
-- Does the table have a companyID column? if statement checking for company id
IF EXISTS(SELECT * FROM Production2.INFORMATION_SCHEMA.COLUMNS WHERE COLUMN_NAME='CompanyID' and TABLE_NAME=@tablename)
BEGIN
if @Counter <= 0 -- make sure loop executes only once.
BEGIN
declare @debug varchar(max)
SET @debug = 'INSERT INTO ' + @Destination_Database_Name + '.dbo.' + @tablename + ' SELECT * FROM ' + @Source_Database_Name + '.dbo.' + @tablename + ' WHERE ' + @Source_Database_Name + '.dbo.' + @tablename + '.CompanyID = ' + CAST(@Company_Id as varchar(10))
print @debug
set @Counter = 1
EXEC(@debug)
--EXEC('INSERT INTO ' + @Destination_Database_Name + '.dbo.' + @tablename + ' SELECT * FROM ' + @Source_Database_Name + '.dbo.' + @tablename + ' WHERE ' + @Source_Database_Name + '.dbo.' + @tablename + '.CompanyID = ' + @Company_Id )
END
END
ELSE
BEGIN
Print 'No'
END
-- if yes then copy data based on companyID in cursor
-- if no check if this is the first time through company loop and copy all data
-- if @firstloop company exists look at information schema
--EXEC('INSERT INTO ' + @Destination_Database_Name + '.dbo.' + @tablename + ' SELECT * FROM ' + @Source_Database_Name + '.dbo.' + @tablename )
-- company logic
SET IDENTITY_INSERT [c365online_script1].[dbo].[tCompany] OFF
FETCH NEXT FROM copyTableDataCursor into @processorder,@tablename;
END
close copyTableDataCursor;
Deallocate copyTableDataCursor;
--INSERT INTO c365online_script1.dbo.tCompany
--SELECT *
--FROM production2.tCompany
--WHERE ISNULL(CompanyID, 0) = 0 -- copy all data where id is equal to zero
--@Destination_Database_Name
--
--EXEC(INSERT + @Destination_Database_Name + '.dbo.' + @tablename + ' SELECT * FROM ' + @Source_Database_Name + '.dbo.' + @tablename + ' WHERE ' + @Source_Database_Name + '.dbo.' + @tablename + '.CompanyID = ' + @Company_Id + ')')
--SET @firstLoop = false;
FETCH NEXT FROM copyCompanyDataCursor into @Company_Id;
END
CLOSE copyCompanyDataCursor;
DEALLOCATE copyCompanyDataCursor;
--Cleanup
DROP TABLE #CompanyID
DROP TABLE #TableList
最佳答案
好吧,错误说明了一切:
An explicit value for the identity column in table 'c365online_script1.dbo.tProperty' can only be specified when a column list is used and IDENTITY_INSERT is ON.
INSERT
语句
必须使用列列表!
INSERT INTO dbo.Table(col1, col2, ...., colN) VALUES(Val1, val2, ...., ValN)
INSERT INTO dbo.Table VALUES(Val1, val2, ...., ValN)
^^^^ no column list defined!!
关于sql - 表中身份列的显式值错误?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19717006/
我是一名优秀的程序员,十分优秀!